[comphappy]

Originally Posted by EricH

F=m*a
Frictional force = mu*N, where N = m*g, where g= 9.8 m/s^2= the gravitational constant acceleration

You're saying that m*a=mu*m*g, right? m cancels out, leaving a=mu*g.

However, the g has been increased by using a fan or something to add downwards force! Guess what? a must increase!

And lbs are NOT a unit of mass, they are a unit of force, which is computed by m*g. Increase g and you increase the force.

Let's look at your scenario: 500 lbs=32f/s^2*x slugs (slug being the English system's unit of mass) 10 lbs =32 f/s^2*y slugs
you are saying that 32f/s^2 * x slugs = 32f/s^2 * y slugs. Cancel out 32f/s^2 and you get x slugs = y slugs. Cancel out the units and x = y. However, because 500/32 = x slugs and 10/32 = y slugs, you get 500/32=10/32, which simplifies to 500=10. This isn't true, is it?

What you said is very WRONG check your equations before correcting me!!!



m*a=u*m*g
becomes
a=u*g

therefore mass does not matter, now if you are useing downdraft gas then the "mass" part of Fn will not equal the mass of the robot. But that is not what I was talking about. Watch your equations.