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More friction questions
We did a few rover wheel robot tests today and based on what I saw I am puzzled. It appeared that a lighter robot would accelerate faster then a heavy robot. Lets see if I can throw out some formulas
Heavier
533.8 N (120 lbs) (54.47 kg on earth) robot
Ff= µ • Fn
x = .05 • 533.8
x= 26.69 N
a=F/m
.4899 m/s^2 = 26.69 N / 54.47 kg
Lighter
400.3 N (90 lbs) (40.82 kg on earth) robot
Ff= µ • Fn
x = .05 • 400.3
x= 20.02 N
a=F/m
.4904 m/s^2 = 20.02 N / 40.82 kg
In standard units, the lighter robot will accelerate 0.0164 ft/s^2 faster.
Based on these numbers, unless I did something wrong, a lighter robot would accelerate faster on regolith then a heavier one (admittedly a small difference). So teams that are talking about adding weights to their robot to add friction should reconsider.
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Last edited by Woody1458 : 11-01-2009 at 18:14.
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