Quote:
Originally Posted by Hastypickle
Sure.
I was thinking maybe the pneumatic actuator could be used, but I don't know how much force that would be able to hold.
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at 60 psi, a 3/4" diameter cylinder has 26.5 pounds of force in the extend direction and 23.5 in the retract direction. If that is not enough, you can step up to a larger diameter.
the equation is f=pa, or force = pressure x area.
for the example above, in the extend direction it is
f = 60 pounds / inch^2 x 3.14 (.375^2) = 26.49 pounds
for the retract, you have to subtract the area of the internal rod,
so the effective area is reduced (0.25 diameter = .125 radius)
f = 60 pounds / inch^2 x (3.14 (.375^2) - 3.14 (.125^2)) = 23.55 pounds.