[Al Skierkiewicz]

Marshall,
It matters not what value you send to the motor, when it starts it is in stall. Since the speed controller is switching the full battery voltage, full stall current is realized even if for a short period of time. It does not matter what the Jaguar is rated for, it will still produce an output that is capable of the full stall current. The only thing that limits the current is the series resistance between the battery and the motor. That is the internal resistance of the battery (11 mohm) the #6 wire (about 2 mohm), the main circuit breaker and 40 amp breaker (much less than 1 mohm), the #10 0r #12 wire to the controller and motor(4 mohm for #10) and the series resistance of the controller (4 mohm). If you are looking at the current alone, it will have ripple (an AC component) as the brush assembly first contacts one winding and then two at a time and then back to one. (The brush is wide enough to hit two commutator segments at the same time) As we have been discussing, temperature, load, battery condition, and state of charge would have to be factored into your calculations to be accurate. That is assuming every motor was made exactly alike. These motors are too inexpensive to be that accurate motor to motor. Your best bet is to monitor the speed of the motor via tach or rotational sensor. The motor output is the only thing you would be really interested in and sensing the output takes all other factors into account.
BTW, check the current rating for the FETs and multiply by three (for three FETs in parallel) to see what the max current ability of the output devices really is.