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Unread 22-05-2009, 08:29
Andrew Schreiber Andrew Schreiber is offline
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Re: pic: Modified vex(Read: Drive Train)

Quote:
Originally Posted by Rick TYler View Post
Have you tried driving this robot yet? With this gearing you might find out that it won't turn very well, and won't achieve anything like its theoretical maximum speed. You'll get a lot better performance by replacing that 12-tooth gear with a 36.
Im going to second the notion of swapping your gears or going with a smaller ratio, right now it is at 3:1 which means every 1 rotation of the motor output shaft you get 3 rotations of the wheel. When you first see this you think, "Sweet I want to go fast that sounds great" the catch is you will not be able to accelerate quickly. This stems from the fact that when you increase speed you decrease torque. Force = torque /(radius*sin(theta)) Using that and F=MA we can calculate your max acceleration to be A = motor_torque/(wheel_radius*robot_mass*sin(theta)) For the sake of simplifying we can assume that sin(theta) = 1. Using that our equation goes to A = motor_torque/(wheel_radius*robot_mass)

Here is the my issue with the way you have this system geared, you may have a top speed of 3*motor_speed but you will more than likely never see that unless you run down a long hallway. Recall v = v_0+a*t, assuming v_0 is 0 (starting from stand still) you could calculate how long it would take you to reach any speed.

As for the turning issue, I'll let someone else show you how to work out the math for that.
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Last edited by Andrew Schreiber : 22-05-2009 at 08:31. Reason: I wrote this far too early in the morning
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