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Unread 17-01-2010, 14:37
sanddrag sanddrag is offline
On to my 16th year in FRC
FRC #0696 (Circuit Breakers)
Team Role: Teacher
 
Join Date: Jul 2002
Rookie Year: 2002
Location: Glendale, CA
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Re: pic: 2010 window motor winch

Quote:
Originally Posted by rsisk View Post
I have to agree with Tom about the great explanation from Joe, but, show some mercy on a software guy and explain the formula use to calculate the 54W below.

TIA
I'll take a shot at it. Work = Force*Distance. Power=Work/Time. So, say we are trying to lift 120lb to a height of 3 feet. Then you need to do 360lbf-ft work to it. To do this in 10 seconds, you need 36lbf-ft/sec of power. There are 550lbf-ft/sec in one Horsepower. There are 746 Watts in one horsepower. So, you need about 49 Watts to make this pull. If you consider the force required to accelerate the robot from zero to loaded-line-pull speed, and inefficiencies and whatnot, more power will be required.
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Teacher/Engineer/Machinist - Team 696 Circuit Breakers, 2011 - Present
Mentor/Engineer/Machinist, Team 968 RAWC, 2007-2010
Technical Mentor, Team 696 Circuit Breakers, 2005-2007
Student Mechanical Leader and Driver, Team 696 Circuit Breakers, 2002-2004
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