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Re: 2=0
You could actually think of it in terms of derivative calculus. Since you're multiplying 0 times infinity, you can also represent 0 as 1/infinity, which will result in infinity/infinity, therefore L'Hopital's rule can apply (and don't think that it equals 1...) Similarly, you can represent infinity as 1/0, which will give you 0/0, and the same thing is true.
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