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Re: Measuring resistance using analog breakout
Easiest to wire would be a voltage divider between a known resistance and your sensor. Think of it like your potentiometer, only with a variable resistance between +5 and GND.
Wiring would be so:
Sensor between SIG and GND
Known resistor between +5V and SIG
You'd get a varying voltage on your SIG equal to the following:
R - constant known resistance
r - variable sensor resistance
V = 5 * r / (r + R)
If you pick an R value about 5-10 times the maximum value of r, you'll end up with a moderately linear signal, if rather small.
Other options are various amplifier and/or transistor circuits which will all be a bit complicated.
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