Thread: 2=0
View Single Post
  #10   Spotlight this post!  
Unread 13-03-2010, 10:10
AndrewJS's Avatar
AndrewJS AndrewJS is offline
Registered User
FRC #2867 (ElkLogics)
Team Role: Leadership
 
Join Date: Oct 2009
Rookie Year: 2009
Location: Indiana
Posts: 6
AndrewJS is an unknown quantity at this point
Re: 2=0

If you are adding like this,
.5 + .5 + .5 + .5 = 2
Etc, then you are really doing a Sigma(2/n) for n times as n approaches infinity. Using the distributive property this sigma expression can be written:
n * (2 / n ) = 2
For all nonzero real numbers, this expression equals 2. At n = 0, there's a hole in the graph, yet its limit is 2.

The key about infinity and zero is that they are not well-defined. It depends HOW you're reaching infinity or zero, not only the fact that you are.
Reply With Quote