Quote:
Originally Posted by Formerly Famous
Maybe it's not traction you need... F=m*a So would a robot that weighs around 110 pounds(maybe 120, which would put it 130 with the battery) so with enough acceleration, (driving right under the tunnel) couldn't they pop it out, and then push them backwards enough to disrupt the strategy? (Not saying I would recommend this, I'm just saying it's possible.)
Just my $.02
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Frictional force is found by taking the force and multiplying it by the coefficient of friction. Really, they're equally important. Having a coefficient of 1.5 will help you a lot more than if you had a coefficient of .5.