Quote:
Originally posted by Clark Gilbert
Was Ken right??? did he win
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Well, I can confirm that Ken was right as far as he went. I got
R = S/(2*(2^0.5) + 3*(3^0.5))
which (if I typed it correctly) is equivalent to Ken's
R = S / ( ( 8^(1/2) ) + 6*sin(120) )
But he only gets partial credit. He didn't do the second part of the problem: solving for
BD. This part gets a little hairier. I get
BD = ((15+4*(6^0.5))/(35+12*(6^0.5)))^0.5*S
So if S=10,
BD = 6.2056272