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Re: Engineering Challenge- Spring Loaded Kicker Edition
Clarification: when you say spring rate, you're referring to the spring constant, right? In other words, bigger spring rate means bigger value of k? In that case. . .
If the motor cannot fully compress the spring, then getting a bigger, harder spring is not going to allow the motor to store more potential energy. In that case the limiting factor is the motor, so just modifying the spring's strength won't do anything for you. So, answer C it is.
Right?
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