Quote:
Originally Posted by disb
I need an axial force of 180 lbs. Now, I have a 2-inch bore piston in the cylinder. Therefore, it will generate roughly 60 PSI correct? - Pressure = force x area of bore.
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Your calculation is correct for the extend direction.
For the retract direction, you have to subtract the cross-sectional area of the shaft. So the required pressure (to achieve the same force) is slightly higher.