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Unread 13-12-2010, 17:22
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Re: CIM no-load current vs applied voltage



Hi Nate. Thanks for your post.

Could you clarify a couple of your statements please?


Quote:
Pmech ~ Pelec (the mechanical (input) power of the motor is approximately proportional to the electrical (input) power of the motor)
What do you mean by the phrase "the mechanical (input) power of the motor"? The only input power to the motor is electrical.


Quote:
Pmech ~ RPM^2 (the mechanical power is proportional to the square of the rotational speed of the armature)
What mechanical power are you referring to here?

For a constant load torque, the mechanical output power of the motor is proportional to the rpm, not the square of the rpm.

For a constant applied voltage and a varying load torque, the mechanical output power first increases and then decreases as the load torque is varied from 0 to stall.


Quote:
RPM ~ V (the rotational speed of the armature is proportional to the input voltage)
The speed is proportional to the applied voltage only when the load torque is zero and the no-load current is small enough to be ignored. Since my question was about not ignoring the behavior of the no-load current, using this relation would be circular reasoning.