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Here is the work and answer for Question 2, along followed by Q3.

Q2 Answer:
R=Coefficient of Resistivity
U=Coefficient of Conductivity
R=1/U
R(total)=R1+R2+R3....
R(total)=(0.3ft[^2]*hr*[degree]F/BTU)+1+25+4+0.5
R(total)=30.8ft[^2]*hr*[degree]F/BTU
U(total)=1/30.8ft[^2]*hr*[degree]F/BTU
U(total)=.032 BTU/ ft[^2]*hr*[degree]F

Question #3
3.) Use the answer to problem 2 to find the heat load on an air conditioner if a house is built of walls like these. The house is 20 feet by 40 feet with 8 foot tall walls, and you may consider the roof has the same construction as the walls (for the purpose of making this problem simpler). Neglect any windows and doors.


That question is a 2 part problem, found everyday while trying to find the load on an air conditioner. This type of problem was taught in class over a 3 day span, after learning about thermal conductivity.
~Mike