Go to Post If you pay attention to every nut job on ChiefDelphi, you'll never reach a decision. - JesseK [more]
Home
Go Back   Chief Delphi > Technical > Technical Discussion
CD-Media   CD-Spy  
portal register members calendar search Today's Posts Mark Forums Read FAQ rules

 
Closed Thread
 
Thread Tools Rate Thread Display Modes
  #1   Spotlight this post!  
Unread 08-08-2002, 11:35
Gui Cavalcanti's Avatar
Gui Cavalcanti Gui Cavalcanti is offline
Robogeek
no team
Team Role: College Student
 
Join Date: May 2001
Rookie Year: 2001
Location: Needham, MA
Posts: 224
Gui Cavalcanti is a name known to allGui Cavalcanti is a name known to allGui Cavalcanti is a name known to allGui Cavalcanti is a name known to allGui Cavalcanti is a name known to allGui Cavalcanti is a name known to all
Send a message via AIM to Gui Cavalcanti
Thanks to everyone that responded so far, I'm learning a lot (everything from rolling friction to why people's robots didn't work as they intended... ;-) )

Lloyd, can you walk through a physics problem combining all of these concepts into one? This is what I think it would look like:

First, find your place on the motor torque/efficiency/speed chart. Then, re-calculate the torque by multiplying it times the gear ratios in your drive train. Then, convert the radius of your wheel into whatever units of length your torque is in (ft-lbs, oz-in, n-m) and divide torque by the covnerted length. Now you have the torque of your wheel.

Now lets see if we can cheat with the units a little bit... you would then proceed to say (if you used the metric newton-meter) "For every meter I move, I can push with such and such newtons of force". You would then take that and subtract the losses to rolling friction, and would get a pretty good estimate of the pushing force of your robot.

To see if you can push another robot, you would take the force you have available for pushing and compare to either their "static" friction, if they are standing still and not pushing their motors, or you would do the same calculations for their drive train and compare the pushing forces - the robots would move in the direction of whoever has the greater pushing force, and the force of them moving in that direction would be equal to the difference of forces in their drive trains.

Yes, no, maybe?

I did take a year of physics, but right now I'm flying by ear.
__________________
Gui Cavalcanti

All-Purpose College Mentor with a Mechanical Specialty

Franklin W. Olin College of Engineering, Class of 2008
Closed Thread


Thread Tools
Display Modes Rate This Thread
Rate This Thread:

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump

Similar Threads
Thread Thread Starter Forum Replies Last Post
traction questions AlbertW Rules/Strategy 2 05-01-2003 17:58
Results of traction test IBApril180 Technical Discussion 3 04-01-2003 18:56
Power, speed, and torque... AGH Gui Cavalcanti Technical Discussion 5 10-11-2002 19:02
Gear Woes Simon G Technical Discussion 14 24-01-2002 16:31
Traction Limited, rather than torque Simon G Technical Discussion 6 23-01-2002 07:08


All times are GMT -5. The time now is 13:10.

The Chief Delphi Forums are sponsored by Innovation First International, Inc.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi