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Unread 04-01-2003, 22:01
Grommit Grommit is offline
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Handy Point Scoring Reference Chart

I created a chart to count the points earned for various combinations of stacks and total boxes. It'll be helpful in competition for on the spot strategizing, and better strategy makes a better game for all of us. Enjoy the season!

Note: I didn't do this, but if you want, it may be helpful to highlight the highest combo(s) in each column. This can give you a goal to achieve in round.

-Shrenik, MVRT #115

Good Luck!
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File Type: xls robopoint.xls (55.5 KB, 264 views)
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Unread 04-01-2003, 22:09
Dinush Dinush is offline
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are you sure you don't want to change 'balls' in D1 to boxes/bins/containers? Something that will describe the objects better than 'balls'? LOL

And Thank You very much for that! I'm sure everyone appreciates it!
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Last edited by Dinush : 04-01-2003 at 22:54.
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Unread 04-01-2003, 22:50
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thats cool

thanks a lot, it will be used.
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Unread 04-01-2003, 22:59
Morgan Jones Morgan Jones is offline
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Re: Handy Point Scoring Reference Chart

Quote:
Originally posted by Grommit
Note: I didn't do this, but if you want, it may be helpful to highlight the highest combo(s) in each column. This can give you a goal to achieve in round.
Determining the highest combination is easier than using the chart: half of the boxes in your zone should be in a stack.
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Unread 05-01-2003, 01:30
Suneet Suneet is offline
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Speaking of charts, did you notice this?

y=a*x^2+b*x+c

y= raw score
a=-1
x=Number of boxes in your highest stack
b=Total number of boxes on your side
c=0, 25, or 50, depending on the #of bots in the middle for you.

I'll admit it's not quite accurate, but that's not my fault.
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Unread 06-01-2003, 00:38
Grommit Grommit is offline
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Unhappy Whoops about the "balls" and "boxes"- still thinking about last year :-P

OOPS! I'm still thinking about soccer balls! Whoops! Hope that doesn't get confusing, sorry about that.

Yep, half the boxes should be in a stack:

f(x) = n(x-n) = nx-x^2
f'(x) = n-2x = 0
x = n/2
f''(x) = -2, therefore n/2 is a maximum.

Yeah, the ax^2+bx+c was a clever hint :-D, especially tricky because it implied that there might be a projectile, since this is a generalization of the parabolic path of a flying object...

Unfortunately the c gets messy.

Have fun with the game! Good Luck!

Do you know if boxes on their side will count as 2 boxes?
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Unread 06-01-2003, 00:41
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Yah, they said that boxes on their side would be 2 boxes. If you get two boxes and do it so they don't sink into each other, that's three. That's what they said on the kickoff thing, at least
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Unread 06-01-2003, 00:44
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This thread may be helpful as well:

http://www.chiefdelphi.com/forums/sh...pagenu mber=1

Just a thought
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Unread 07-01-2003, 21:04
Grommit Grommit is offline
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I saw the kickoff but I'm not sure they'll do 2 times on 1 box

Although the kickoff said that the height counts, it just feels unlikely that one box will or should be counted as a stack of two. Two as three is plausible, and supported by the kickoff, but it just seems odd that a pox that's just been knocked over is a stack of two. Has there been any official word on this?

Thanks.
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Unread 07-01-2003, 21:22
DanL DanL is offline
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At kickoff, they used a tall point with red rings at the different "stack heights" (first ring at height of one box flat-down, second ring at height of second perfectly meshed box, etc). If a box lands on it's width (short side), then the length's going to be pointed skywards, and so it'll stick up into the 2-box height. So yeah, if you don't have any stacks, but one box lying on its width, that'll count as a stack of two, or atleast thats how it seems from what they showed at kickoff.
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