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#1
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I got a problem with my IR sensors code. Everything works ok until the robot reaches the end of the white line. I thought i'd be cleaver and wrote an if statement that says if rc_sw 1,2 & 3 =0 then go straight, however the robot goes into a left hand loop.
Any help or suggestions would be greatly appreciated!! Here is the code I wrote: FullAutoMode: if rc_sw2=1 then straight: if rc_sw1=1 & rc_sw3=0 then turnleft: if rc_sw3=1 & rc_sw1=0 then turnright: if rc_sw1 & rc_sw2 & rc_sw3=0 then straight: goto endir: straight: debug "staight",cr p1_y = 234 p3_y = 254 goto endir: turnleft: debug "left",cr p1_y = 84 p3_y = 127 goto endir: turnright: debug "right",cr p1_y = 127 p3_y = 84 goto endir: KillAuto: endir: |
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#2
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I believe the problem is centered around improper use of the &. Try replacing them with the keyword AND as well as splitting up that last if into multiple equlaties joined with the AND keyword.
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#3
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Code:
if rc_sw2=1 then straight: if rc_sw1=1 AND rc_sw3=0 then turnleft: if rc_sw3=1 AND rc_sw1=0 then turnright: if rc_sw1=0 AND rc_sw2=0 AND rc_sw3=0 then straight: |
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#4
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Thanks for the help. It does not make a whole lot of sence since "&" and "and" are the same thing, however it works now!
_______________ Very funny Scottie....NOW BEAM DOWN MY CLOTHES! |
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#5
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Quote:
Taking your previous code, assume sw1=1, sw2=0, sw3=1. Evaluate left to right: sw1 & sw2 & sw3 => 1 & 0 & 1, which is 0. Then apply the comparison evaluator, 0=0, which evaluates to true. Thus if any of the switches are 0, this will evaluate to true. |
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#6
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Oh! I understand now! I just had an id-10-t error!
Once again, thanks for your input. |
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