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#1
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Horsepower of Kit Motors?
I know the drill motor spec sheet tells a Horsepower rating.. and I know some teams have done their own testing to verify spec sheet promises..
Has anyone found maximum horsepower ratings for all the kit motors this year? If not all.. at least some? i.e. FP, Globe, and Van Door |
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#2
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Gadget,
Again you have to refer to the tables for output power as related to RPM on the motors in question. There is a conversion factor, Watts x 0.001341 = Horsepower. This will allow you to convert from watts to horsepower. You can find more conversions at http://www.watb.net/info/c_factor/power.shtml |
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#3
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Problem is, only the Drill and Chiaphua motors say the Watts Out at max power or the efficiancy of the Watts In
Last edited by Gadget470 : 03-05-2003 at 15:42. |
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#4
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You can calculate the Watts Out at max power yourself, you just need to know how.
Check out my lecture notes: "WRRF motor selection workshop lecture notes... " It's under the technical sections in white paper. Here is a link to it: http://www.chiefdelphi.com/forums/pa...C&pagenumber=2 |
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#5
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I've always used 746 W = 1 H.P.
A 400 kW Mercedes engine has 300 H.P. in the U.S. And since electric motors are really efficient, use Watts Out = > 0.9 times Watts In = Volts x Amps. (The approximation is useful because your input data are approximations too.) If you have to figure Watts out, you can also use torque times revs : W - F x d = F x [v x t] = (T / arm) x (rps x arm x 2 x pi) J = N x m = (N.m/m) x (cirumferences-per-second x length of circumference) = (N) x (length) = F x d = W |
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#6
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To anyone following this thread, or who just may want to know, the following is the maximum horsepower ratings for the 2003 motors.
Drill: .504 CIM: .4562 F-P: .1987 -w/ GB: .121 Globe: .053 Van: .0889 Window: .0074 Information found with the help of Ken and Al's posts, thanks a lot guys ![]() Last edited by Gadget470 : 04-05-2003 at 18:29. |
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#7
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#8
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#9
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Yeah that is not really smart to do unless you know your dealing with rare earth magnet motors which generally have high efficiencies. This really is not smart to do with the motors First gives us. |
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#10
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#11
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I guess to go sideways, you could throttle back the Drill motors to match the F-P motors, but then wouldn't you have .1987 * 4 = 0.7948 effective horsepower versus 1.08 horsepower for 2 Drill motors alone? Am I correct in assuming that WildStang was able to move faster in a forward direction that in a sideways direction? |
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#12
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The values I posted are the maximum values of horsepower.
Horsepower is a relationship between RPM and Torque. When running the drill with no load and no gearbox, you won't get .5 HP out of the motor. Take the following equation: Torque * (RPM/5252) = Horses Now yes, you may be getting more horsepower to wheel A and B and less on C and D, but that's OK. The wheels were "speed matched" where the final stage of gear reduction left all wheels with the same speed by having different ratios. Wildstang, and others using the same setup, achieved a certain speed and horsepower by matching the speeds while having different torque values to the sets of wheels. If I'm not mistaken, correct me if I'm wrong please, WS probably had drill putting out ~.4 HP and the F-P's putting out ~.05 .4 + .4 + .05 + .05 = .9 HP |
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#13
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Maximum Power (in Watts) output is typically calculated as:
Power = (Max Freespeed / 2) * (Stall Torque / 2) * Conversion Factor Maximum Power (in HP) can then be calculated as: HP = Power / 746 Really, horsepower is a misleading and useless number. Power output (in Watts) is by far a better and more accurate comparison. When coupled with efficiency, it's the best comparison. Horsepower and Watts are the same thing, but HP is an Imperial Unit and the Watt is the SI (metric) unit. SI units are by far better units to use, because you will use less conversion factors (less screw-ups) when moving between Power output and Electrical input. However, remember to mention you are using SI units in all your calculations or you might end up like NASA! Last edited by Jnadke : 05-05-2003 at 13:14. |
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#14
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Last edited by DougHogg : 06-05-2003 at 02:25. |
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#15
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To answer many of the above questions...
The different motors we used were matched to different transmissions so that the wheels were close to match. Any fine tuning could then be done in software. Knowing which side the drills were on then set what side of the robot was used for power, pushing, etc. Using watts for motor output power helps solve a number of problems in design. You know what the output power is and you can measure the input electrical power, so with a little calculation you can determine efficiency. Power out/power in=efficiency. So what does that tell you? The power lost in the conversion has to go someplace. The result is heat. So in the case of the Bosch motor running at 376 watts out with 672 watts input, efficiency at 56%, then 296 watts go into heat. Yes that's like three 100 watt light bulbs in each motor doing nothing but generating heat. That is the heat that changes the motor internal resistance, melts the bearing lubricants, detaches the fan and unsolders the motor wires. In many cases in electrical systems, it is very important to get rid of the heat generated in the system. Things like CPU heatsinks and power supply fans in your computers prevent that heat from building up to point where the physical properties start to change. In solid state electronics, the heat generated internally can cause more current to flow, which in turn causes more heat, and so on. The tech term is "thermal runaway" and many devices are designed to shut down when the temp gets too high. The three terminal regulator, 7805, will cutback on current or shut down completely if it gets hot, for instance. |
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