Maximum Score

[Aignam]

Has anyone figured out the maximum score that an alliance can score in a single match?

Sorry if this question has already been presented. I searched the term 'maximum score' and found nothing relevant.

[HolyMasamune]

the highest plausible score a team could get is 410, with 10x5 balls and 2x10 balls with a 2x multiplier in the mobile goal, 13x5 balls, 2x10 balls (stolen from the other team), and a 2x multiplier in the stationary goal and then 2 robots hanging on the bar at the end

that is unless some team can manage to balance the 2x ball on one pvc

[Jake Lewis]

what if you could put two 2X balls on top of a goal?? would that multiply by four? it is possible to do...since the pvc bends, you could get one ball into the goal and balance another on top...

[matt111]

well i assume u dont mean ur QPs which would be ur oppenents score. if u win that is all the matters

[Aignam]

Originally Posted by Jake Lewis

what if you could put two 2X balls on top of a goal?? would that multiply by four? it is possible to do...since the pvc bends, you could get one ball into the goal and balance another on top...

Let's avoid this particular discussion here.

[kevin.li.rit]

560 If you can fit an infinite amount of balls into your two goals. If you score 2, 10pt balls. And 12 starting human player balls right?

[KenWittlief]

theres 18*5 in the ball release = 90
theres 6 starter balls per side * 5 = 30
theres 2 release balls per side * 10 = 20

thats 140 in small balls

double them all, that 280

hang both bots, that 380 points for 'your side' of the field

assuming you want you opponent to score high and leave them alone

if not, you cant get all 52 small balls in play into your two goals (the two goals can hold approx 35 balls) - so the absolute max score depends on that limtation.

[kevin.li.rit]

The 10 ball doesn't get doubled?

[KenWittlief]

Originally Posted by Coffeeism

The 10 ball doesn't get doubled?

sure it does!

[kevin.li.rit]

Originally Posted by KenWittlief

sure it does!

Originally Posted by KenWittlief

theres 18*5 in the ball release = 90
theres 6 starter balls per side * 5 = 30
theres 2 release balls per side * 10 = 20

thats 140 in small balls

double them all, that 280

hang both bots, that 380 points for 'your side' of the field

assuming you want you opponent to score high and leave them alone

if not, you cant get all 52 small balls in play into your two goals (the two goals can hold approx 35 balls) - so the absolute max score depends on that limtation.

Yes, well I wasn't sure since you didn't double the 2, 10pt balls in your totals.

[kevin.li.rit]

Knocking only one ball will trigger the release I assume?

[KenWittlief]

Originally Posted by Coffeeism

Knocking only one ball will trigger the release I assume?

yes, either one - but if your opponent puts a release ball back onto your tee, then all the balls on the field jump back up into the ball release bin

(not really :c)

[Dan Richardson]

The answer to your question.. tho it might not be possible is the highest score is 660pts

w/ 2 multipliers all balls and 2 bots hanging

technically tho.. w/ the 2 opponent bots hanging they can get 100 pts

however as we all know getting this many points would be useless except in finals

[KenWittlief]

Thulium - you forgot the 6 'starting balls' behind the wall on each end of the field - see drawings in section 4.1

Coffeism: I include 2 release balls in the 140 points count

and double all the 'small balls' is 280 - small size, not small value.

top score possible using only whats on your side of the field = 380 points

making it to the elimination rounds: Priceless!

[kevin.li.rit]

My mistake.