Teach Genia How to Program and Win a Prize

[Eugenia Gabrielov]

So, many people are aware of my lack of technical or programming knowledge.

However, I was so inspired today by a conversation between me and user "nehalita" that I had to create a little something to aid my progress in the technical world.

Seriously speaking, I've always been interestsed in it, but always failed before I got to the programming self-study books. So here's what I know so far.

Chocolate == chip, Oreo '= chip, but chocolate == oreo

So uh, accelerate my knowledge, so maybe myself (and some other programming inept people) will be able to follow the entire mess.

Edit: And it's a really really awesome prize!

Thanks
- Genia

Btw: With all due respect to programmers, this thread is created as a self-make fun of. I admire you guys like mad, you make the robots work . So appreciate my interest.

[nehalita]

why don't we try if-then statements.
like:

if (genia understands programming)
{
    miracle = 1; //1 means true, so there IS a miracle
}
else
{  
   normal = 1; //normal is true
}

those slashes are comment thingers so when you program, you can keep track of what you write.

SOOO what i'm saying is, if genia understands programming, then it's a miracle but otherwise, all is normal.

[DarkJedi613]

heres a good site with very very short tutorials:

www.ronsguide.com

[DarkJedi613]

Originally Posted by nehalita

why don't we try if-then loops.

That's actually not a loop, just a statement.

[nehalita]

Originally Posted by DarkJedi613

That's actually not a loop, just a statement.

<L on forhead>
...you're right. mistake x.x'. let me fix that....
</L on forhead>

[DarkJedi613]

heres a simple loop

1 int amountOfLoops = 0;
2 while (amountOfLoops <= 100) {
3     amountOfLoops++; //adds one to amountOfLoops
4     System.out.println(amountOfLoops); //outputs amountOfLoops to screen
5 }

1 - Defines the variable amountOfLoops (which is just the name) as an integer equal to zero.
2 - Conditional statement saying that if amountOfLoops is less then or equal to 100 do what is within the brackets.
3 - "Increment" amountOfLoops, which just means add one to it.
4 - Prints the variable amountOfLoops to the screen (i.e. it would do 1 2 3 4 etc.).
5 - End Loop

[Xufer]

Yummmmmmmm GLOMP (6:17:00 PM): hahahaha
Yummmmmmmm GLOMP (6:17:05 PM): we're working out some code
mobile xufer (6:17:29 PM): oh
mobile xufer (6:17:54 PM): just to make people laugh i made my code humerous ...
Yummmmmmmm GLOMP (6:18:00 PM): LOL
mobile xufer (6:18:13 PM): alot my variables end in izzle
Yummmmmmmm GLOMP (6:18:20 PM): hahahah
Yummmmmmmm GLOMP (6:18:21 PM): I have to see this
mobile xufer (6:18:28 PM): ill show you a section of it
mobile xufer (6:18:44 PM):
if (-1 <= leftizzle[2] < (inch*80.5))
{pwm01 = 180;}
Yummmmmmmm GLOMP (6:19:21 PM): SO CONFUSING
Yummmmmmmm GLOMP (6:19:22 PM): argh
Yummmmmmmm GLOMP (6:19:27 PM): post that on my programming thraed
Yummmmmmmm GLOMP (6:19:28 PM): and explain it

alright so heres a section of it

 
Here are the main variables
#define pi 3.14159265358979  //defines pi
#define wheel (8*pi)             //defines the circumferance of our wheels
#define wheeltick (wheel/32) // defines the ammount that the wheel moves in each tick
#define inch (1/wheeltick) // sets each tick into an inch form for ease of calculating distances
/*---------------------------------------------------*/
//basicly whats done here is reseting all the values to 0
int leftizzle[3] = {0, 0, 0};
int rightizzle[3] = {0, 0, 0};
int startposit; //not covered in this code segment, is the switch for case statements
int step = 0; // not covered in this code segment, but i do the auton in steps so that it resets its self throughout each phase
//that concludes resetting the values

/*------------------------------------------------*/
//now onto this bit of code

if (-1 <= leftizzle[2] < (inch*80.5))
	{pwm01 = 180;}

basic setup is

if (condition)
{action}

the condition here is the value of leftizzle if the value is true then the motor will go forward at the above speed
to explain the condition if the variable leftizzle[2] the second part of the leftizzle set marked by an x (0,x,0)
if leftizzle is greater than or equal to -1 and less than 80.5 inches then the robot moves forward...

hope that wasnt too confusing

[DarkJedi613]

that's actually some of the messiest code I've ever seen...

[Eugenia Gabrielov]

Well I figured a bit of it out!

so on Ron's Guide thingy that DarkJedi linked, you've got this # thing which means comment yes? I'm learning! But I'll keep looking

Thanks for the code. And thanks to quite a few people for helping me develop my first code which I'll edit in here in a minute or two.

[DarkJedi613]

Originally Posted by Eugenia Gabrielov

Well I figured a bit of it out!

so on Ron's Guide thingy that DarkJedi linked, you've got this # thing which means comment yes? I'm learning! But I'll keep looking

Thanks for the code. And thanks to quite a few people for helping me develop my first code which I'll edit in here in a minute or two.

What language are you looking under? PHP is the only "real" programming language that Ron's Guides gives tutorials for.

And yes #, // and /* */ are all used to comment.

Was there any particular language you were planning on learning? If not you should think about it so you can download a compiler and mess around with it.

[Eugenia Gabrielov]

Here it is everyone! My first code! thank you to all who contributed.
Most especially darkjedi

passesLegendOfMaxOnHeavy(person) {
     if (person==Genia) {
          return true;
     } else {
          return false; 
     }
}
if(passesLegendOfMaxOnHeavy(Genia)) {
     awesome=1;
} else {
     triesAgain=1;
}

There you have it.

[nehalita]

nice job. i think you're getting it =) according to my code up there, we have a miracle =P

[jgannon]

Originally Posted by Eugenia Gabrielov

Here it is everyone! My first code! thank you to all who contributed.
Most especially darkjedi

passesLegendOfMaxOnHeavy(person) {
     if (person==Genia) {
          return true;
     } else {
          return false; 
     }
}
if(passesLegendOfMaxOnHeavy(Genia)) {
     awesome=1;
} else {
     triesAgain=1;
}

There you have it.

I think you need a return type on your function, and a type for the argument. Also, since the C18 compiler doesn't support boolean data types, you'll have to define them another way:

#define true 1
#define false 0
#define Genia 461

unsigned char passesLegendOfMaxOnHeavy(int person) {
     if (person==Genia) {
          return true;
     } else {
          return false; 
     }
}

if(passesLegendOfMaxOnHeavy(Genia)) {
     awesome=1;
} else {
     triesAgain=1;
}

The #define statement for "Genia" allows you to create "friendly" names for people. For instance, you could also add:

#define dlavery 116
#define JVN 229

You wouldn't need those definitions if "person" was some sort of object defined in its own class, rather than an int, but it's been so long since I wrote classes in C, I wouldn't even know where to start. Trying to keep C/C++ and Java straight in your head is no walk in the park.

*removes nerd hat* I'm such a dork...

Nonetheless, awesome, Genia. You might just be a CS major in training, if you're willing to trade in your social life.

[Xufer]

Originally Posted by DarkJedi613

that's actually some of the messiest code I've ever seen...

yea i don't pride myself on neatness infact my code isn't formatted or even commented at all i just did the commenting for Eugenia...

[DarkJedi613]

Originally Posted by Xufer

yea i don't pride myself on neatness infact my code isn't formatted or even commented at all i just did the commenting for Eugenia...

Besides that you didn't follow anything though. Usually things are named for what they mean, not for just random words. Plus second words are usually capped.