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#1
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How much pressure is needed to pop these poof ball into the center goal with a 2" bore and 4" piston from the tip of the ramp? Is it possible? What equation can I use to find this out? HELP! ![]() |
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#2
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Re: Cylinder Force Calculation
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The force a clyinder puts out is just pressure times area. Area being pi*r^2 For force on the retract, subtract the cross sectional area of the rod. Also, have you guys already ruled out a spinning wheel shooter? It is not as hard as it may seem. You can build it it one day if you were focused on it. |
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#3
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Re: Cylinder Force Calculation
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Last edited by Arkorobotics : 18-01-2006 at 00:21. |
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#4
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Re: Cylinder Force Calculation
It's more an issue of flow and volume, I would suggest printing out the manual and setting up a test situation and see if you can get what you are thinking about to hit the ball fast enough and hard enough to get what you are hoping for. You may be surprised by your results.
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#5
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Re: Cylinder Force Calculation
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#6
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Re: Cylinder Force Calculation
the equations you are looking for relate force, mass, acceleration, velocity, distance and time
you need to specify the length of the cylinder-throw, the mass of the ball, and the velocity you desire the pressure will then fall out as the calculated force divided by the area of the face of the (circular) internal piston plate. Force = mass times acceleration distance = 0.5 * acceleration * time^2 velocity = acceleration * time (and you can average the velocity = final speed / 2) to get the time remember that mass is kilograms and force is newtons. (or slugs and pounds). something else (that has been discussed in other threads): the flow of air through the valves and hoses in the kit of parts is not that fast - probably not fast enough to laungh a ball. You will most likely need to hold the cylinder back with a release pin (a pin that blockes its forward motion) and precharge the cylinder with air, then pull the pin to fire the launcher. This means if you want a 4" throw you might need an 8" cylinder, with the release trigger pin half way down its travel. and you might also need to take the fitting off the far end of the cylinder, to allow the air to escape without restriction. Last edited by KenWittlief : 18-01-2006 at 09:47. |
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#7
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Re: Cylinder Force Calculation
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#8
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Re: Cylinder Force Calculation
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then released when you implement this way, is like an air-spring |
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#9
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Re: Cylinder Force Calculation
decided to draw a diagram
1. the release pin is blocking the cylinder from extending more than half way 2. the cylinder is charged with 60PSI 3. the release pin is pulled. The business end of the cylinder has no fitting, so the low pressure air flows out freely 4. the ball is launched into tomorrow! 5. a mechanical stop prevents the end of the piston from slamming the inside end of the cylinder (not shown) 6. use a spring or surgical tubing to pull the piston back when the pressure valve is closed (not shown either) Last edited by KenWittlief : 18-01-2006 at 14:42. |
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#10
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Re: Cylinder Force Calculation
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#11
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Re: Cylinder Force Calculation
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Ever see the pumpkin-chuckers, the giant air cannons that launch a 10" pumpkin about a mile away? they have huge air valves that someone pulls with a foot long handle. we dont have those valves, so you need to get the air in the cylinder first (precharge) and then pull the mechanical pin out of the way. |
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#12
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Re: Cylinder Force Calculation
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#13
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Re: Cylinder Force Calculation
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I know a cylinder with 60psi slamming it back and forth looks fast, but not compaired to something like pulling a spring back and letting it go. By precharging the cylinder, blocked half way, you are creating an air-spring. scroll back up and look at the drawing in post #9 in this thread. |
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#14
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Re: Cylinder Force Calculation
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