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#17

10-02-2011, 02:22

John G

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FRC #0399 (Eagle Robotics)

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Join Date: Nov 2009

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Location: Lancaster, CA

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Re: pic: In_CIM_erator

Quote:

Originally Posted by AdamHeard

Mechanical power is torque x speed.

Stepping down from 18 to 12V is a 2/3 change.

Power = 2/3Torque x 2/3 speed. Works out to the power at 12V being 4/9 that of 18V.

Ok. I did Power = w/t; w = Fd; F = torque *r. I thought distance and time would stay constant, so I ended up with 2/3 by just changing the torque. Thank you.

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