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Physics Quiz 7
Figure1 attached shows the top view of a vehicle with standard wheels attempting to rotate counter-clockwise but not yet moving because the torque being applied to the wheels is too low. The +Y axis is the "forward" direction. Assume the following: - Four identical standard non-steerable wheels of radius "r" - Wheels are located at the corners of a rectangle - Axis of each wheel is parallel to the X-axis - Coefficient of friction "mu" is the same in all directions - The same magnitude torque "tau" is being applied to each wheel - Let f2 = trackwidth/wheelbase - The right wheels are being torqued “forward” - The left wheels are being torqued “backward” - The vehicle is in static equilibrium - CoM aft of CoG. Vehicle is on a flat, level floor. - Let f1 = (distance from CoG to CoM)/(distance from CoG to the point midway between rear wheels) - Let W be the weight of the vehicle. - Fn is the total friction reaction force of the floor on the bottom of wheel #n, and Fnx Fny are its components. n= 1,2,3,4. Problem: Find the torque tau in terms of mu, r, W, f1, and f2 required to break the static friction and start the vehicle rotating. |
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