Maximum Number of Points

[Jnadke]

What about the DQ multiplier?


Many people are miscounting containers. There are 8 containers per alliance, and 29 in the middle. That is 45 containers.


23 containers * 22 containers = 506 pts
2 robots * 25 pts/each = 50 pts
556pts * 2 DQ multiplier = 1112 pts


1112 points is the maximum a team can achieve.

[Bduggan04]

Originally posted by IsabelRinging
Oooh, but don't forget the situation where the height of the stack is higher than the actual number of boxes in the stack.

So...

24 stack height x 22 boxes + 50 = 578 points

0 stack x 0 boxes + 50 = 50 points

578 + 50(2) = 678 QPs/EPs

One problem... There aren't 46 tubs.


The HIGHEST score is actually:

2(23 Stack Hieght x 22 boxes + 100)= 1212 points

Where does the first 2 come from? If an opponent is disqualified you get twice your own score. It isn't likely, but I believe last years high score was set by a team that profited from a rule similar to this.

I'm editing this because while I type this 3 other people posted as well (Only on CD) .

Anyway Someone else said that you couldd stack them on their side to get 942 (946?? I don't remember). Just double it and that's the highest.

1884 Points (Good Luck)

[Joel J]

hrm.. seems to me.. that:

Red
Stacked: 23
On Ground: 23
On Ramp: 2
23 x 23 + 50 = 579

Blue
Stacked: 0
On Ground: 0
On Ramp: 2
0 x 0 + 50 = 50

The kicker? Blue gets disqualified, thus making the final score of the red alliance: 2*579, or 1158.

This is impossible.. if anyone were to do this, I would shake their hand.

[Joel J]

Originally posted by Bduggan04
One problem... There aren't 46 tubs.


The HIGHEST score is actually:

2(23 Stack Hieght x 22 boxes + 100)= 1212 points

Where does the first 2 come from? If an opponent is disqualified you get twice your own score. It isn't likely, but I believe last years high score was set by a team that profited from a rule similar to this.

hrm.. May I ask where you got that 100 from?

[IsabelRinging]

Originally posted by Bduggan04
One problem... There aren't 46 tubs.


The HIGHEST score is actually:

2(23 Stack Hieght x 22 boxes + 100)= 1212 points

Where does the first 2 come from? If an opponent is disqualified you get twice your own score. It isn't likely, but I believe last years high score was set by a team that profited from a rule similar to this.

The stack of 24 box height actually consists of 23 boxes. One of them is stacked on its side or upside down, making the height of the stack exceed 23 boxes. They demonstrated how this can happen during kickoff.

[AJ Quick]

Originally posted by Bduggan04
2(23 Stack Hieght x 22 boxes + 100)= 1212 points

So then:

2(36 Stacked the long way x 22 boxes + 50) = 1684 ??

[Bduggan04]

Originally posted by Joel J.
hrm.. May I ask where you got that 100 from?

Sure. From What I gathered from the kickoff, if a robot is on top of another, the bottom robot gets an extra 25 points for having them on the ramp. If both of your robots cariied two others you could get 100. However, this should be cleared up by first.

[Noelle]

Hey, the highest possible score will always come from having an equal pile of boxs in the stack and on the ground. That's where the whole quadatic equation comes into place. (parabola would have the highest point where ax squared= bx)

[Bduggan04]

Originally posted by IsabelRinging
The stack of 24 box height actually consists of 23 boxes. One of them is stacked on its side or upside down, making the height of the stack exceed 23 boxes. They demonstrated how this can happen during kickoff.

Yeah I forgot that, and actually you could go much higher than 24.

[Noelle]

Sure. From What I gathered from the kickoff, if a robot is on top of another, the bottom robot gets an extra 25 points for having them on the ramp. If both of your robots cariied two others you could get 100. However, this should be cleared up by first.


No, the top robot just gets the scoring points of the bottom robot, 25 if the bottom gets them, 0 if the bottom robot doesnt. But what if the top robot isn't totally in the scoring area?

[Bduggan04]

Originally posted by Noelle
Hey, the highest possible score will always come from having an equal pile of boxs in the stack and on the ground. That's where the whole quadatic equation comes into place. (parabola would have the highest point where ax squared= bx)

Good call. That's where the 942 in an earlier post comes from. That would make 1884 the higest score.

[Katie Reynolds]

Anyone take into account yet, that the top bin of a stack can be turned on it's side to give you the height or one more bin? Remember: It's not how many bins you have, it's the height that counts!

- Katie

[Noelle]

Originally posted by AJ Quick
So then:

2(36 Stacked the long way x 22 boxes + 50) = 1684 ??

36 stacked the long way? how is that?

[OneAngryDaisy]

Originally posted by Noelle
36 stacked the long way? how is that?

even though its probably impossible, use your imagination- stack the boxes so that their longer side faces up in the air-

[Bduggan04]

Originally posted by Katie Reynolds
Anyone take into account yet, that the top bin of a stack can be turned on it's side to give you the height or one more bin? Remember: It's not how many bins you have, it's the height that counts!

- Katie

This was already mentioned.