Gearbox Calculations

[Ether]

Originally Posted by nickcvet89

Hey, I am having a hard time determining output speed and torque from the CIM-U-LATOR gearbox using the 2 RS-550 banebots motors. Can anyone explain what formulas I need to determine this? All help is appreciated.

Banebots 550-12:

19,300 rpm free speed

70.5 ozin stall torque

85 stall amps

CIM-U-LATOR:

Gear reduction is 2.7:1

... so 2 550's on a CIM-U-LATOR would be

free speed = 19,300/2.7 = 7148 rpm*

stall torque = 2*70.5*2.7 = 381 ozin*

stall amps = 2*85 = 170 amps


Is that what you were asking?


* neglecting gearbox efficiency losses