|
|
|
![]() |
|
|||||||
|
||||||||
![]() |
| Thread Tools | Rate Thread | Display Modes |
|
#16
|
||||
|
||||
|
Quote:
Also the mouse would have to be larger than those of last year to have much momentum. These bins weigh 4.885lbs without the rivets and they flex. Mice really don't seem that useful. |
|
#17
|
||||
|
||||
|
Hehe I found a loophole.
Quote:
|
|
#18
|
||||
|
||||
|
Quote:
|
|
#19
|
||||
|
||||
|
and the loophole is closed
![]() |
|
#20
|
||||
|
||||
|
Think Outside the box.
Imagine 2 robots 60 pounds each that are connected by a tether. On each side, one knocks down boxes, one defends, OK I realize the weight disadvantage of 60 verses 130 but I bet you could give a pretty good defense. Again, as for the ramp you just Reel in the mouse to get 100% on the platform. 2 60 pound robots may be able to defend the platform better than 1 130# bot...that would need to be tested of course |
|
#21
|
||||
|
||||
|
wow. That's a good thought. two small bots instead of 1 big one.
and to fix the size constraint you might have you could make it so the teather parks itself on top of the main bot in the end, I suppose ![]() |
|
#22
|
|||
|
|||
|
At kick off, Dave Lavery said (and I misquote) that, if two robots were "stacked" the top robot takes on the attributes of the bottom robot. Ie. if the bottom robot is on the ramp, then so is the top one. If the bottom robot is off the ramp, then so is the bottom one.
In the event that a robot fragments, the "robot" is considered to be the part that contains the robot controller. Hence, if a bot "splits" and the bit that contains the robot controller ends up on a robot that is on the ramp, both robots should count as being on the ramp. (I suspect that they will clarify to make this illegal, however.) But, you could imagine a "mouse bot" that is everything except the robot controller. Put the RC part on your partner who drives on the ramp. Your 120lb "mouse bot" can go have a ball and not worry about getting back to the ramp. Andrew Team 356 |
|
#23
|
|||
|
|||
|
I posted a similar question in a different thread, but thought it might be answered quicker here......
isn't there enough room for all four robots on the platform??? if so... then what is the need to park on top of someone elses robot? |
|
#24
|
|||||
|
|||||
|
Umm. In short, don't assume that all of the robots will end up in the same position they started in. Some may be quite a bit larger.
|
|
#25
|
||||
|
||||
|
Two things
First, every year they talk about robots getting lifted up on top of things (and no one builds such things) I believe thats where trhe comment was coming from. At one point they had even included a stretcher in the game (also never used) to try to get this stuff to happen Second. I believe 100% of the robot needs to be on the ramp. According to the rules that is. So the idea of a 10 # brain and 120# platform wouldn't be that useful in this circumstance (But thats a neat idea) Also I think you can fit 4 robots up there is 12 foot long. Of course it won't be a cooperative venture so I think we won't see that occuring that often BTW I found teh bins (whatever they are gonna be called) at Walmart for $3.90 a piece I bought all 40 of the color in the game |
|
#26
|
|||
|
|||
|
My idea for a tether was at first to try to climb on the opponenents robot. But I have figured out that this would gain me no points. But since being on top doesn't count, imagine a tether that can slide under a part of the opponenets robot and partially lift it to negate the points. This may be illegal too, but I don't see a why you could climb on top of another bot, potential damaging it and not pick it up from underneath.
|
|
#27
|
||||
|
||||
|
Quote:
by parking a robot on top of someone else's, it makes the entire robot heavier, causing a greater normal force, resulting in more friction... if you are on another team's robot, (i'm not sure how the scoring goes there...) then u cause them to consider moving out of or staying on the platform |
![]() |
| Thread Tools | |
| Display Modes | Rate This Thread |
|
|