Window motor or FP W/ Gearbox?

[kevin.li.rit]

Originally Posted by pfreivald

I suggest that you consult your local physics teacher or mechanical engineer. He/she can teach you the relationship between power, torque, and angular speed -- and how to convert that into a linear time on a 22-inch pull.

With the torque/power specifications of a particular motor/gearbox combination, you will then have all the tools necessary to make the right decision for the application.

22lbs * 1.5 inch lever arm for a 3 inch spool = 33lbs*inch=528 oz*inch

528oz*inch / 121 (reduction in FP gearbox) = 4.33 oz*inch

RPM @ 4.33oz is approximately 19000RPM at motor, 157 RPM at output.

24 inches/s assuming 100% efficiency after the motor output.

Using specs for the 801-0673 FP