Bridge reset

[JP Carlin]

So i made the measurements and for what I intend on working with I have 2 pneumatics with a 1.5 inch bore and I believe an 10in stroke. I found a table giving the extending force of a pneumatic and my results are more then double what the table says so if someone could just double check my math and tell me if they have the same thing.
so force=area * psi
(3.14)(1.5in)*(60psi)=282.6lbs of force
table says that the force with this should be 106lbs

Here the link to the table I found
http://www.usfirst.org/sites/default... %20Manual.pdf

any idea on which force I should use

[kevin.li.rit]

Originally Posted by JP Carlin

So i made the measurements and for what I intend on working with I have 2 pneumatics with a 1.5 inch bore and I believe an 10in stroke. I found a table giving the extending force of a pneumatic and my results are more then double what the table says so if someone could just double check my math and tell me if they have the same thing.
so force=area * psi
(3.14)(1.5in)*(60psi)=282.6lbs of force
table says that the force with this should be 106lbs

Here the link to the table I found
http://www.usfirst.org/sites/default... %20Manual.pdf

any idea on which force I should use

106

It is pi*.75inch^2 * 60 PSI = 106lbs

This is because a 1.5 inch bore has a radius of .75 inches.

[Shaun Coon]

your math is correct

[DonRotolo]

PI R Squared is the area of a circle.
We know this because we are the PI-O-Neers...

[JP Carlin]

Originally Posted by DonRotolo

PI R Squared is the area of a circle.
We know this because we are the PI-O-Neers...

I see what you did there thanks for the corrections cant believe i mixed up diameter and radius but o well

[JP Carlin]

One last question and then i should have this pretty much down.

Ive only used these equations using metrics before so if
Torque=Force * Distance * sin of angle

Am i using distance as inches or feet when calculating this

[kevin.li.rit]

Originally Posted by JP Carlin

One last question and then i should have this pretty much down.

Ive only used these equations using metrics before so if
Torque=Force * Distance * sin of angle

Am i using distance as inches or feet when calculating this

Either one.

106lbs with a 1 ft lever arm would be 106Ft*lbs or 1272inch*lbs.