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Further thoughts.
If you have 3 stacks of 5 bins, 4 bins laying scattered about the score zone, and a stack of 7 bins, this is how the score will be calculated: [(3*5)+4] * 7 Not any other way. You don't need to bother with the 7 bins in the first half of that equation. More examples: You have a multiplier stack of 4 bins, and one bin lying next to the stack 1*4=4. |
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