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#1
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Re: Is it possible to control a Jaguar with a potentiometer?
I believe the answer to your question is yes...kinda.
You can use a potentiometer to control a jaguar but first you will have to run to radioshack(the shack) and pick up a few things. You should be able to generate the appropriate signal using a basic 555 timer circuit. I am on my phone righht jow so i do not have the specifics but there are enough web pages a quick google for 555 timer circuit will provide the circuit. The 555 timer circuit uses two resistors to determine the frequency and pulse width of the ouput signal. You should be able to use a poteniometer for the pulse width resistor to create a very simple circuit on a breadboard thst will control a jaguar output via a potentioneter without using any type of digital control. Sorry this explanation may be better suited to the slightly more advanced reader but a little research online should be enough to enlighten even a beginner. |
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#2
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Re: Is it possible to control a Jaguar with a potentiometer?
I made a post on chief Delphi a few years ago showing a circuit that does exactly that. You might want to search for it.
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#3
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Re: Is it possible to control a Jaguar with a potentiometer?
Quote:
http://www.chiefdelphi.com/forums/sh...3&postcount=34 |
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#4
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Re: Is it possible to control a Jaguar with a potentiometer?
I was wondering if it might not be possible to set the Jag to Analog Position Control Mode using an RS-232 or CAN connection, telling it to head for the 1.5V position. Then set only a proportional response, no I or D.
As you swing the pot to one side the motor should move in one direction, with increasing power relative to the "error" in the Pot. Swing it the other way and the motor should turn in the other direction. Not that there is anything wrong with the other ways, but is there a reason this wouldn't work? I haven't played with the Jags for years, so I'm just working from the manual here... Jason P.S. Not that I don't use 555 timer circuits, but I'd probably be tempted to use a PIC or Arduino to generate the serial code for the Jag, but they could also generate PWM code quite easily. A 16f88 or similar would be a one chip solution... easily programmable in Great Cow Graphical Basic, using a PICKIT2 or PICKIT3 programmer and a breadboard. Last edited by dtengineering : 27-09-2012 at 03:20. |
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#5
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Re: Is it possible to control a Jaguar with a potentiometer?
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#6
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Re: Is it possible to control a Jaguar with a potentiometer?
Here is a link to what we use:
http://gadgetgangster.com/find-a-pro...projectnum=206 You need to lower the value of the output current limiting resistor then it works great. I suggest you add a current probe to your test rig so you can measure current while you are testing your systems. A 10 gauge wire 12" long works perfect. Use that wire as a shut, it will measure 1 millivolt for 1 amp. There are several threads here that discuss that scheme. Do a search for stangsense. Here is a photo of our rig that can control two motors. In this photo the motor is running and drawing 3 amps. By having this information you can know that your motor is running within the correct range and that the magic smoke will remain. -Hugh |
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#7
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Re: Is it possible to control a Jaguar with a potentiometer?
I have found that a Pololu RC controller to be handy for some robot testing.
http://www.pololu.com/catalog/product/1352 You could do the same thing with an arduino, but the control application that you would run on the laptop makes it easy to use. Can also read analog 0 to 5 volts so it can double as a sensor checker. |
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#8
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Re: Is it possible to control a Jaguar with a potentiometer?
Using the CAN/RS-232 method only works if always want to have a laptop or MSP430 or something else to always connected to the CAN buss. If you are going that far there is not much to gain.
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#9
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Re: Is it possible to control a Jaguar with a potentiometer?
I'm really impressed with how much effort we'll go to, to avoid buying a $25 servo tester.
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#10
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Re: Is it possible to control a Jaguar with a potentiometer?
Quote:
Just like Ham radio operators, robot people are cheapskates. Thus the attraction of building a solution for $4 to avoid spending $25. |
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#11
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Re: Is it possible to control a Jaguar with a potentiometer?
Do you have access to a Vex controller? Small and portable, remote RC control.
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#12
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Re: Is it possible to control a Jaguar with a potentiometer?
Quote:
True, but the PIC wouldn't need external capacitors or resistors.... well, other than the pot.But I gotta admit... the 556 even with the resistors and the caps would be slightly cheaper than the PIC... much cheaper if you didn't already have some programming hardware around. I've used both 555's and microcontrollers in projects... I tend to like the microcontroller route because when I screw something up I can usually fix it by upgrading the software. (Why, yes. I do use Windows, why do you ask?) Jason |
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#13
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Re: Is it possible to control a Jaguar with a potentiometer?
If it were me I'd just use BDC-Comm and build a CAN to Serial Cable and a CAN terminator and use a laptop (or netbook with a USB to serial adapter).
Then again, I did write a paper on doing such so my opinion is kinda biased? But really, all one needs is a laptop (with windows and serial means ^ ), a junked serial cable, two RJ12 (or an RJ 12 and an RJ 11), and a 100 ohm resistor. That could be built for say, $5 (or less if you already have CAN parts to your disposal). It's also pretty easy if you know how to use a multimeter and how to solder. The one I built to make my paper took like 10 minutes to make, and that was with pausing to snap pictures. |
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#14
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Re: Is it possible to control a Jaguar with a potentiometer?
My quick calculations for somebody to buy the resistors, capacitor and 555 would be $6.30
TI's launch pad $4.30 Laptop CAN method $1.80 (assuming you have a computer) RC Tx/Rx $36.50 (wireless method for "safe testing") Jumper wires $0.12 PS you only "need" the terminator for high baud rates. Not critical for testing Last edited by anthonyttu : 28-09-2012 at 09:24. |
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#15
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Re: Is it possible to control a Jaguar with a potentiometer?
Quote:
RS-232 method: $0.10 for a diode. |
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