Trouble understanding timed tasks in Periodic vi

[JamesAnthony]

My team is using the 2-wire VEX motor 393 to "kick" the frisbee into a wheel that is meant to shoot it. We only want to turn it once so I figured that since the motor is 100 rpm then one revolution would take 600 ms. I know that to do a timed event, you must use the Periodic Tasks VI but I'm not sure on how this works in a block diagram (I was a text based programmer before this). I was thinking that our primary joystick, "Joystick I", would trigger some sort of case structure when Button 1 is pressed and then have the motor, "Initator", turn for 600 ms. I've looked at resources such as Team 358's very helpful LabVIEW resources but I don't understand why the outside while has a wait for 10 ms. Attached is the resource that I am referencing.

Thanks for any help that you can give me.