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#1
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Re: 2583's Octocanum Modules
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It's hard to see how much mechanical advantage they have--looks like close to none--but 2 x pi x (1.5 in/2)^2 x 60 psi = 212 lbs; well more than enough. |
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#2
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Re: 2583's Octocanum Modules
The issue is that they are not using a 1.5 inch bore. Two 1.0625 inch bore will probably not be able to lift up the robot (and remember to take into account the added weight from battery and bumpers).
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#3
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Re: 2583's Octocanum Modules
Quote:
2 x pi x (1.0625 in/2)^2 x 60 psi = 106 lbs, which is well below comfort without a 2:1 or better mechanical advantage. |
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#4
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Re: 2583's Octocanum Modules
Interesting concept.
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#5
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Re: 2583's Octocanum Modules
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#6
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Re: 2583's Octocanum Modules
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