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Unread 17-02-2014, 19:24
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Re: Math Quiz: Parabola Path

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Originally Posted by Ether View Post
Hint#2: the top and bottom boundary curves are not true quadratics.
Graph of upper and lower boundary curves
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Unread 03-03-2014, 00:02
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Re: Math Quiz: Parabola Path

Can I give the answers in parametric form?

Spoiler for parametric plot equations:
xlower(t) = t - 0.0866 t / √(1 + (0.0866 t)2)
ylower(t) = -0.0433 t2 - 1 / √(1 + (0.0866 t)2)

xupper(t) = t + 0.0866 t / √(1 + (0.0866 t)2)
yupper(t) = -0.0433 t2 + 1 / √(1 + (0.0866 t)2)
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Unread 03-03-2014, 09:51
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Re: Math Quiz: Parabola Path

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Originally Posted by RyanCahoon View Post
Can I give the answers in parametric form?
You got it

Reps to you !


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Unread 06-03-2014, 17:57
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Re: Math Quiz: Parabola Path


Is it possible to represent Ryan's parametric equations in explicit form y=f(x) ?

Or even implicit f(x,y)=0 ?


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Unread 11-03-2014, 16:45
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Re: Math Quiz: Parabola Path

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Originally Posted by Ether View Post
Is it possible to represent Ryan's parametric equations in explicit form y=f(x) ?

Or even implicit f(x,y)=0 ?
Does anyone have access to Mathematica?


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Unread 11-03-2014, 18:32
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Re: Math Quiz: Parabola Path

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Does anyone have access to Mathematica?
http://www.wolfram.com/mathematica/trial/
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Unread 11-03-2014, 18:44
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Re: Math Quiz: Parabola Path

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Thank you, I am aware of that. For a variety of reasons, I don't install or use trial software.

Are there any Mathematica gurus out there in CD land?


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Unread 11-03-2014, 20:07
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Re: Math Quiz: Parabola Path

As a function of x, it will describe the upper boundary on one side and the lower on the other. It does exist, but it is very ugly. I will try to remember to post it later.
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Unread 11-03-2014, 20:25
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Re: Math Quiz: Parabola Path

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Originally Posted by maths222 View Post
As a function of x, it will describe the upper boundary on one side and the lower on the other.
Yes, there will be 2 separate functions - one for the upper boundary and one for the lower (just like Ryan's parametric equations).

Quote:
It does exist, but it is very ugly. I will try to remember to post it later.
Excellent. Would you please post both a "typeset" version and a "cut-and-paste programming" version? (see example in attachment)

Thank you.
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Unread 12-03-2014, 09:49
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Re: Math Quiz: Parabola Path

The display ones will come later.

Eq 1:
Code:
−11.547344110855*sqrt(((x^(2)+133.34115601449)/(2.*x*sqrt(x^(2)+133.34115601449)*abs(x)+x^(4)+267.68231202898*x^(2)+17779.86388728)))*sign(abs(x)+x*sqrt(x^(2)+133.34115601449))-((0.0433*(abs(x)+x*sqrt(x^(2)+133.34115601449))^(2))/(x^(2)+133.34115601449))
Eq 2:
Code:
(((11.547344110855*x*(x^(2)+133.34115601449)-11.547344110855*sqrt(x^(2)+133.34115601449)*abs(x))*sqrt(((1)/(−2.*x*sqrt(x^(2)+133.34115601449)*abs(x)+x^(4)+267.68231202898*x^(2)+17779.86388728))))/(abs(abs(x)-x*sqrt(x^(2)+133.34115601449))))-((0.0433*(abs(x)-x*sqrt(x^(2)+133.34115601449))^(2))/(x^(2)+133.34115601449))
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Unread 12-03-2014, 12:33
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Re: Math Quiz: Parabola Path

Quote:
Originally Posted by maths222 View Post
The display ones will come later.

Eq 1:
Code:
−11.547344110855*sqrt(((x^(2)+133.34115601449)/(2.*x*sqrt(x^(2)+133.34115601449)*abs(x)+x^(4)+267.68231202898*x^(2)+17779.86388728)))*sign(abs(x)+x*sqrt(x^(2)+133.34115601449))-((0.0433*(abs(x)+x*sqrt(x^(2)+133.34115601449))^(2))/(x^(2)+133.34115601449))
Eq 2:
Code:
(((11.547344110855*x*(x^(2)+133.34115601449)-11.547344110855*sqrt(x^(2)+133.34115601449)*abs(x))*sqrt(((1)/(−2.*x*sqrt(x^(2)+133.34115601449)*abs(x)+x^(4)+267.68231202898*x^(2)+17779.86388728))))/(abs(abs(x)-x*sqrt(x^(2)+133.34115601449))))-((0.0433*(abs(x)-x*sqrt(x^(2)+133.34115601449))^(2))/(x^(2)+133.34115601449))
Hmm.

Your equations differ from Ryan's by about 0.01 near x=5

Also, the x-intercept of your upper-boundary equation differs from Ryan's by about 0.03

Given the number of decimal places in your equations, I would have expected them to be closer.


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Last edited by Ether : 12-03-2014 at 13:49.
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Unread 13-03-2014, 11:26
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Re: Math Quiz: Parabola Path



Jacob,

Can you re-run Mathematica using the following parametric equations instead?

Code:


x_lower = t + 2*a*t / sqrt(1 + (2*a*t)^2);

y_lower = a*t^2 - 1 / sqrt(1 + (2*a*t)^2);


x_upper = t - 2*a*t / sqrt(1 + (2*a*t)^2);

y_upper = a*t^2 + 1 / sqrt(1 + (2*a*t)^2);
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Unread 13-03-2014, 19:00
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Re: Math Quiz: Parabola Path

I used a TI-Nspire and logic to arrive at my equations, so they are probably wrong. I will take a look at them this weekend.
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Unread 16-03-2014, 16:52
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Re: Math Quiz: Parabola Path


Are there any Mathematica gurus out there?

Wondering if there is a solution for the following problem:

Find explicit functions y=y_lower(x) and y=y_upper(x) for the following parametric equations:

Code:


x_lower = t + 2*a*t / sqrt(1 + (2*a*t)^2);

y_lower = a*t^2 - 1 / sqrt(1 + (2*a*t)^2);


x_upper = t - 2*a*t / sqrt(1 + (2*a*t)^2);

y_upper = a*t^2 + 1 / sqrt(1 + (2*a*t)^2);
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