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[Ether]

Originally Posted by Analog

The curves make sense, as each is a stepped based on the current load, i.e. the larger the current, the lower the output voltage at that current over time, since the internal resistance is making up the rest of the cell voltages.

Yes, the larger the current, the lower the output voltage at that current over time.

But I think you missed the point I was making: For equivalent drained Ah, the higher current drain rate should have a lower voltage.

200A*30s = 6000As = 1.66Ah
400A*15s = 6000As = 1.66Ah

So the voltage at 400A at 15s at should be lower than the voltage at 200A at 30s. But it's the other way around in the figure.


This is just a minor observation and in no way detracts from the impressive accomplishment of the work and the report.