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#1
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FRC Team 271 12cim 2 speed transmissions. Lets play some defence at championships this year (2015).
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#2
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Re: FRC Team 271 teaser
So... do the other 6 CIMS get cheesecake-tethered to another robot to satisfy [R18]?
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#3
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Re: FRC Team 271 teaser
Please tell me that entire transmission powers one can grabber.
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#4
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Re: FRC Team 271 teaser
I will do no such thing!
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#5
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Re: FRC Team 271 teaser
Making an electric gokart with that?
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#6
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Re: FRC Team 271 teaser
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#7
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Re: FRC Team 271 teaser
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#8
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Re: FRC Team 271 teaser
Is that a power take-off I see?
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#9
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Re: FRC Team 271 teaser
I would love to see this thing in person
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#10
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Re: FRC Team 271 teaser
It would make sense if they were min-cims... them being unlimited this year and all...
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#11
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Re: FRC Team 271 teaser
Thats beautiful.
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#12
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Re: FRC Team 271 teaser
Peak? 133A * 12v * 12 motors = 19152w, or 25.6HP?
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#13
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Re: FRC Team 271 teaser
From Andymark's website each CIM produces 337Watts at maximum power.
337 per CIM * 6 motors = 2022 Watts per transmission assuming no power loss. 1 HP = 745.7 Watts (1) 2022/745.7 = 2.71 HP per transmission. Edit: This is why using stall current for power doesn't work for DC motors ![]() from this page In other news, I just realized why some people use 5310RPM as the freespeed of a CIM. Assuming the CIM behaves like described in the MIT coursework, peak power occurs at 2655RPM and in the middle of the RPM range. Doubling 2655 yields 5310RPM as the max RPM for a CIM (1) Wolfram Alpha Last edited by Dunngeon : 11-04-2015 at 03:50. Reason: Power curve in DC motors |
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#14
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Re: FRC Team 271 teaser
Those are our 2014 transmissions on top of our 2013 transmissions, but that now give me an idea *opens inventor and starts a 12CIM can grabber*, I mean who needs a drive train anyway!
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#15
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Re: FRC Team 271 teaser
That's 33.6lbs of CIMs alone, let alone the gears (heck the gears look like steel too) on that thing. Would it be possible to get a weight on those? what on earth needs that much power?
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