|
|
|
![]() |
|
|||||||
|
||||||||
|
|
Thread Tools | Rate Thread | Display Modes |
|
#25
|
||||
|
||||
|
Re: pic: Small CIM in wheel swerve
You can skip the whole lesson on Maxwells equations and simply use the quite linear DC motor equations:
Current = ((Stall Current – Free Current) / Stall Torque) x Torque Load + Free Current Torque Load = (Current – Free Current) x Stall Torque / (Stall Current – Free Current) Speed = - (Free Speed / Stall Torque ) x Torque Load + Free Speed Power = 3.14 x Speed x Torque Load / 30 The efficiency is simply power out over power in, Eff = Power / (Current x Voltage) For a CIM motor: Free Speed: 5,310 rpm (+/- 10%) Free Current: 2.7A Maximum Power: 337 W (at 2,655 rpm, 172 oz-in, and 68A) Stall Torque: 2.42 N-m (343.4 oz-in) Stall Current: 133A You run peak current at the highest torque load. As an aside, it's no mystery why six CIM drives pop their main breakers with regularity. |
| Thread Tools | |
| Display Modes | Rate This Thread |
|
|