Go to Post F.I.R.S.T. Troubleshooting Rule #1 - If you work on software, the problem is always with hardware. If you work with hardware, the problem is always with software ;) - Redneck [more]
Home
Go Back   Chief Delphi > FIRST > Robot Showcase
CD-Media   CD-Spy  
portal register members calendar search Today's Posts Mark Forums Read FAQ rules

 
 
 
Thread Tools Rate Thread Display Modes
Prev Previous Post   Next Post Next
  #15   Spotlight this post!  
Unread 07-12-2015, 01:05
BBray_T1296's Avatar
BBray_T1296 BBray_T1296 is offline
I am Dave! Yognaut
AKA: Brian Bray
FRC #1296 (Full Metal Jackets)
Team Role: Mentor
 
Join Date: Jan 2011
Rookie Year: 2010
Location: Rockwall, TX
Posts: 947
BBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond reputeBBray_T1296 has a reputation beyond repute
Re: "Waffle" East Angelbots 1339 Offseason Project

Churro tubes are a Solid Mechanics example of one of the worst cross-sectional profiles imaginable to transmit torque.

Internal shear stress distribution in a pure torsion model is linear with radius. That is to say the further-out parts of the shaft (from the neutral axis) carry more rotational shear stress than the further-in parts.

In a circular shaft, from the center, the 0 to r/2 part of the shaft handles (1/2)^4 of the torsion (6.25%) while the outer half (r/2 to r) of the radius carries the remaining 93.75%.
This means a shaft with a hole in the center of half the diameter is only 93.25% as stiff, but with %75 the weight, making it a reasonable trade-off.
This also means a solid shaft with half the radius will deflect the same amount (radians/unit length) as the full shaft with just 6.25% the load and 25% the weight.

The churro tube with its "snowflake" cross section gains its weight savings by carving out the outer sections of the shaft. This is removing much of the primary torsion carrying material, leading to a horrendous torsional rigidity. I don't have the time to run numbers unfortunately, but it has to be really pitiful.

Note that in tension/compression or beam shear proximity to the neutral axis is irrelevant, making a churro tube no different than any other shaft with identical x-sectional area in these properties.
Beam bending moments are probably pretty decent due to the I-beam-like sections so churro tube may be a reasonable choice there

tl;dr Churro tube has an exceptionally poor torsional stiffness per unit weight, for weight savings use a hex axle with a hole drilled in it instead
__________________
If molecular reactions are deterministic, are all universes identical?

RIP David Shafer: you will be missed


 


Thread Tools
Display Modes Rate This Thread
Rate This Thread:

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump


All times are GMT -5. The time now is 11:18.

The Chief Delphi Forums are sponsored by Innovation First International, Inc.


Powered by vBulletin® Version 3.6.4
Copyright ©2000 - 2017, Jelsoft Enterprises Ltd.
Copyright © Chief Delphi