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#1
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How many CIMs in your drivetrain?
I started as a FIRST student in 2004. to my knowledge we've always used 2 CIMS per side on the standard "tank drive" type setup. We used mecanum wheels once which required independent drive of 1 CIM per wheel.
Does anybody have any (scientific) input on using only 1 CIM per side? (2 total) how about 6 CIM drive? |
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#2
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Re: How many CIMs in your drivetrain?
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We also did octocanum for about five years, and could beast through just about everyone...except for 6 CIM drivetrains, despite being geared down about as preposterously low as you could get, and with great traction. I would strongly recommend not going to one per side--you'll lose every pushing match you get into with a four-CIM drivetrain, and each of those CIMs are going to draw more current, work harder, get hotter, and drain your battery more than four or six. The only advantage is weight, and it's not a good enough tradeoff. |
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#3
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Re: How many CIMs in your drivetrain?
has anyone ever done a drivetrain with more than 6 motors? (not including steering for swerve)
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#4
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Re: How many CIMs in your drivetrain?
Here's a quick calculation using MCALC to compare one CIM drawing 60 amps at 12 volts vs two CIMs each drawing 30 amps at 12 volts: Code:
Motor Calculator build MCALC_2014d 2/3/2014 1255pm
Select motor:
1)CIM 6)FP0673 d)FP2719 f)FP9012 g)FP9015 h)FP9013 j)MiniCIM
a)am-0912 b)am-0914 7)DensoL 8)DensoR c)Denso0160 k)BAG u)UserDefined
2)RS395 3)RS540 4)RS550 e)RS775-12 5)RS775-18 m)RS555 n)am-0915
r)am-2193 s)am-2235 t)RS390 v)RS545 p)am-2161&2194
w)VEX2177hi z)VEX2177std 1
CIM FR801 001, AM802 001A @ 12.00 volts:
@ free (no load):
oz-in Nm rpm rpm% amps watts out watts heat eff%
0.0 0.000 5310 100.0 2.7 0.0 32.4 0.0
@ stall:
oz-in Nm rpm rpm% amps watts out watts heat eff%
343.4 2.425 0 0.0 133.0 0.0 1596.0 0.0
@ max power:
oz-in Nm rpm rpm% amps watts out watts heat eff%
171.7 1.212 2655 50.0 67.8 337.1 477.1 41.4
@ max efficiency:
oz-in Nm rpm rpm% amps watts out watts heat eff%
42.8 0.302 4648 87.5 18.9 147.1 80.2 64.7
Select input:
1)oz-in 7)watts_in 3)rpm 5)amps b)rpm&s 8)eff%
2)Nm 6)watts_out 4)rpm% 9)volts a)rpm&ozin m)main menu x)exit 5
enter amps: 60
CIM FR801 001, AM802 001A @ 12.00 volts:
oz-in Nm rpm rpm% amps watts out watts heat eff%
151.0 1.066 2975 56.0 60.0 332.2 387.8 46.1
Select motor:
1)CIM 6)FP0673 d)FP2719 f)FP9012 g)FP9015 h)FP9013 j)MiniCIM
a)am-0912 b)am-0914 7)DensoL 8)DensoR c)Denso0160 k)BAG u)UserDefined
2)RS395 3)RS540 4)RS550 e)RS775-12 5)RS775-18 m)RS555 n)am-0915
r)am-2193 s)am-2235 t)RS390 v)RS545 p)am-2161&2194
w)VEX2177hi z)VEX2177std u
Enter the following motor specs in the order and units indicated,
separated by spaces or tabs:
volts stall_ozin free_rpm stall_amps free_amps
12 686.8 5310 266 5.4
UserDefined-> 12.0 686.8 5310 266.0 5.4 @ 12.00 volts:
@ free (no load):
oz-in Nm rpm rpm% amps watts out watts heat eff%
0.0 0.000 5310 100.0 5.4 0.0 64.8 0.0
@ stall:
oz-in Nm rpm rpm% amps watts out watts heat eff%
686.8 4.850 0 0.0 266.0 0.0 3192.0 0.0
@ max power:
oz-in Nm rpm rpm% amps watts out watts heat eff%
343.4 2.425 2655 50.0 135.7 674.2 954.2 41.4
@ max efficiency:
oz-in Nm rpm rpm% amps watts out watts heat eff%
85.6 0.605 4648 87.5 37.9 294.3 160.4 64.7
Select input:
1)oz-in 7)watts_in 3)rpm 5)amps b)rpm&s 8)eff%
2)Nm 6)watts_out 4)rpm% 9)volts a)rpm&ozin m)main menu x)exit 5
enter amps: 60
UserDefined-> 12.0 686.8 5310 266.0 5.4 @ 12.00 volts:
oz-in Nm rpm rpm% amps watts out watts heat eff%
143.9 1.016 4197 79.0 60.0 446.6 273.4 62.0
332 watts output mechanical power 388 watts waste heat two CIMs each drawing 30 amps at 12 volts: 447 watts output mechanical power 273 watts waste heat |
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#5
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Re: How many CIMs in your drivetrain?
We did a 2 CIM drivetrain last year, but Recycle Rush was definitely a special case; you didn't want to accelerate quickly or drive very fast. We're starting with 4 this year, and if we change it, we'll be going to six.
I've read about people considering 4 CIM + 4 min-CIM designs for Mecanum and 4-wheel Killough, but was unable to find any examples that had been built and played. |
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#6
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Re: How many CIMs in your drivetrain?
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That year we ran 4 CIMs + 4 Mini-CIMs in our shifting 8in Mecanum Drivetrain. Looking back, mecanum probably wasn't the best choice that year with the heavy defense ( ), but we sure tried our hardest to make it work. For the most part it did, and we were able to handle many defensive situations with the great traction of the extremely wide wheels, but the cons far outweighed the benefit. With 8 CIM-motors, we had the potential to run 320 Amps of current into our drivetrain before any of the individual 40A breakers would trip. Even operating well below that, there was incredible risk for popping the main breaker, not to mention browning out components, both of which happened in matches on multiple occasions. In high gear, any defensive situation was almost always a brown-out and radio reboot on the field. In low gear, we had maybe 10 seconds before a brown-out. With the current sensing capabilities of the new PDP, careful software could allow a team to more safely run this kind of setup, but back then, it was far more risk than the team could effectively manage or I would ever recommend. |
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#7
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Re: How many CIMs in your drivetrain?
We talked about using 6 cims for a all terrain off season robot. I've got a couple 36v motors I'm going to donate though.
The team is considering 2 CIM drive this year. I'm not recommending that, especially with tank treads. I think they will change their minds when they see how poorly it performs after the chassis is built. Hopefully we can drive it this weekend. Maybe I'll be proven wrong though.. |
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#8
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Re: How many CIMs in your drivetrain?
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I know that 2 cims will be capable of more torque, I'm just wondering how noticeable it will be from the perspective of the driver. |
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#9
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Re: How many CIMs in your drivetrain?
Quote:
Quote:
447+273 = 720 total watts consumed (two CIMs) They both consume the same power @ 12 volts @ 60 amps, but you get more output mechanical power and less waste heat with two CIMs. So you don't need as many amps with the 2 CIMs to get the same output power as 1 CIM. |
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#10
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We had 2 added 2 more today. Only problem is we were only able to get one screw in each Cim. We will try more probably making a tool to get in there but, we sadly have run a drive train an entire season using 1 screw per Cim and can verify it works.
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#11
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Re: How many CIMs in your drivetrain?
You're specifying X amount CIMs at 60 amps. It is manufacturing a theoretical load that will require 60 amps.
The load is different. What happens if you specify a load? |
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#12
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Re: How many CIMs in your drivetrain?
We are going to be running either a 6 CIM drive or a 4 CIM drive depending on our lift mechanism. At this point in the build we are using the 6. 3 on each side.
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#13
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Re: How many CIMs in your drivetrain?
General rule of thumb for motors (at least what I was taught in college): A motor is most efficient when run exactly at the rated power output. More or less will result in a drop in efficiency. Obviously the latter is a better scenario than the latter, but in terms of % efficiency, all else being equal, going overkill isn't an improvement.
That said, it's far easier for a 2 cim drive to get pushed past the rated output, and given that batteries are usually recharged between matches, the time when efficiency (for realistic practical FRC purposes) counts is under full load (read: shoving match), so that's why a 2 cim drive will overheat and (probably) draw more amps in such a scenario. The reason 6 cim drives lead to brownouts is not a motor issue per se; it's simply that such a drivetrain has more capability than a single battery can provide (at a voltage that the control electronics/VRMs can handle). So, realistically, in a FRC legal robot, you'll never see the full potential of a 6 cim drivetrain. You may see more than a 4 cim, sure, but you'll probably never get to full load simply because the battery can only give so much power (internal resistance is the limiting factor assuming good battery wiring). Hence the need for brownout prevention for such drivetrains. |
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#14
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Re: How many CIMs in your drivetrain?
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Maximum power occurs when P(out)=radial velocity * torque is maximized, which is at half free speed and half stall torque. Maximum efficiency occurs when P(out) / P(in), or (radial velocity * torque) / (current * voltage) is maximized. This always occurs somewhere between the maximum power point and free speed (it varies from motor to motor depending on free current). |
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#15
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Re: How many CIMs in your drivetrain?
Quote:
The max efficiency occurs at a higher speed. EDIT: Jared beat me to it. Last edited by Ether : 22-01-2016 at 01:10. |
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