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#1
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Re: Math Quiz 10
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Last edited by Ether : 01-10-2016 at 11:18. |
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#2
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Re: Math Quiz 10
Using the analysis results from Gus' last post, and the hint in post 13, the final solution step is quite straightforward. Open a LibreOffice spreadsheet and populate columns A and B with the XY data. Label the data in column A x_data. Label the data in column B y_data. In column C put degrees from 139 to 199 stepping by 1. In column D put radians equivalent of column C: colD=colC/180*pi() Initialize cell O2 to zero Label cell P2 "_b" and initialize it to one. Label cell L2 "_a" and put the formula = O2/180*pi() In column E put the 2-parameter polar equation model: r = (colD - _a)^_b In column G put formula colE*COS(colD)+1.16 Label the data cells in this column x_model In column H put the formula colE*SIN(colD)-0.3 Label the data cells in this column y_model In cell M2 put the formula SUMXMY2(x_data,x_model) + SUMXMY2(x_data,x_model). This is the objective function for the Solver. Tools | Solver Target Cell M2 Minimum By changing cells O2 : P2 Solve click continue a couple of times to refine the value |
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#3
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Re: Math Quiz 10
When I saw θb, my mind read "theta flat"
. In any case, I found the answer a different way: Assuming that r=θb, we know that dr/dθ = bθb-1, so that r/(dr/dθ) = θ/b. I therefore calculated the slope of r using the numbers given. The intercept of the line with r=0 is therefore (a good approximation to) θ0, and the slope is (approximately) 1/b. My spreadsheet gave a θ0 of 2.007223652 radians, or 115.0054438 degrees, and a b=0.499973651. These did not work out exactly, but a bit of tweaking found that 115 degrees and 0.5 worked "exactly". Using the mathematical polar coordinate system centered on 1.16, -0.3 and rotated 115 degrees counterclockwise, the equation is simply: r = √θGoing back to calculate the original series: D = [139..199]An updated spreadsheet with a "double check" tab is attached. The maximum error in the reconstructed x and y is less than 10-14. |
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