|
|
|
![]() |
|
|||||||
|
||||||||
|
|
Thread Tools | Rate Thread | Display Modes |
|
#18
|
|||||
|
|||||
|
Re: numerical solution of differential equations
Quote:
Quote:
if x=Ae√3t/√2, then x'=√3Ae√3t/√2/√2 (chain rule) and x''=3Ae√3t/√2/2 (chain rule again) = 3x/2. Edit: I knew there was more to it, and just figured out the other part: x''=3x/2 ==> x= Ae√3t/√2 + Be-√3t/√2 Last edited by GeeTwo : 25-12-2016 at 04:47. |
| Thread Tools | |
| Display Modes | Rate This Thread |
|
|