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Unread 01-07-2003, 00:23
DanL DanL is offline
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LED's, resistors, computers... ohm my!

Hey-o... if anyone's still around this time of year, I've got a question for ya.

I want to attach 2 LED's in series to a 12v power supply from my computer (EFY5366x). I just wanna make sure I have the the calculations for the resistor right (see diagram below).

Their total current draw is 60mA, and their total voltage drop is 3.6V. So
12v - 3.6v = 8.4v

And from V=IR, we get
R = 8.4v / (60/1000)A = 140 ohm.

Is that right, or do I not understand the problem at all?

Also, I seem to remember that you're supposed to put the resistor before the LEDs... is this right?

[Edit]Just realized the LED's I linked to aren't the 1.8v 30mA I put into the diagram... for sake of argument, let's say I was using 1.8v 30mA LED's...
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Dan L
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Last edited by DanL : 01-07-2003 at 00:31.
 


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