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LED's, resistors, computers... ohm my!
Hey-o... if anyone's still around this time of year, I've got a question for ya.
I want to attach 2 LED's in series to a 12v power supply from my computer (EFY5366x). I just wanna make sure I have the the calculations for the resistor right (see diagram below). Their total current draw is 60mA, and their total voltage drop is 3.6V. So 12v - 3.6v = 8.4v And from V=IR, we get R = 8.4v / (60/1000)A = 140 ohm. Is that right, or do I not understand the problem at all? Also, I seem to remember that you're supposed to put the resistor before the LEDs... is this right? [Edit]Just realized the LED's I linked to aren't the 1.8v 30mA I put into the diagram... for sake of argument, let's say I was using 1.8v 30mA LED's... Last edited by DanL : 01-07-2003 at 00:31. |
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