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#16
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Quote:
f(t) = sin(t) + 2 Then: f'(t) = cos(t) f''(t) = -sin(t) Integrating twice yields: f''(t) = sin(t) + C1t + C2 However, we are guaranteed that the sinusoid is translated, and should have no t term, thus C1 MUST be zero. With your above equation it's the same idea. c1 must be zero. Seriously, putting aside my lame and incorrect argument above that has no validity at all, heat transfer equations (specifically fin analysis) are without any doubt in my mind the absolute worst equations I have ever come across. I'm actually impressed you found an equation for fins that is so simple... probably because it's in it's most generic form. Anyway, if you really like I can post the most obscene equation I can find in my heat transfer book. I remember it being very long, and containing many variables that took other equations to define what those variables mean, and so on and so on several times. - Patrick |
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#17
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Lol, well Pat, according to a materials engineer like my dad, those "aren't hard at are to know by heart." Pfft.
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#18
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I don't know about crazy, but I've always enjoyed this:
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#19
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Re: Crazy Math Formulas
Not much of a challenge but definatly a time filler.
pi/2 = 2/1 + 2/3 + 4/3 + 4/5 + 6/5 + 6/7 + 8/7 + 8/9 + 10/9... It just repeats on and on. |
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#20
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Re: Crazy Math Formulas
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#21
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Re: Crazy Math Formulas
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pi/2 is ~1.57, the first number on the other side of the = is a 2. and you keep adding more? hm.. |
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#22
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Re: Crazy Math Formulas
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#23
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Re: Crazy Math Formulas
it give exactly half the value of pi thats all the pi/2 means. it means pi divided by 2 = 2/1 ...
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#24
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Re: Crazy Math Formulas
Quote:
after a quick google i found the real formula: pi/2 = 2/1 * 2/3 * 4/3 * 4/5 * 6/5 * 6/7 * 8/7... echos just made a symbol error ![]() |
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#25
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Re: Crazy Math Formulas
Thanks for the correction it was a little fuzzy in my mind. I found that one on google a while back ago and made a c program out of it. but i lost the source code.
Code:
unsigned double float pi;
unsigned int top;
unsigned int bottem;
unsigned int count;
int main()
{
top = 2;
bottem = 1;
pi = top/bottem;
while(count < 10000)
{
pi *= top/bottem;
bottem += 2;
pi *= top/bottem;
top += 2;
count++
}
printf ("pi = %f", pi*2);
}
Last edited by echos : 22-01-2004 at 16:59. |
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#26
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Re: Crazy Math Formulas
Try solving problem #2 in this thread:
http://www.chiefdelphi.com/forums/sh...ad.php?t=27647 Aside from that, I recommend looking at Olympiad problem books with inequalities in them, you can get some crazy formulas in there. Talk to me on AIM or send me a PM if you want me to suggest some good books... I know quite a few. |
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