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Unread 16-10-2003, 22:04
Argoth Argoth is offline
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physics equations

could anybody tell me the physics equations for friction and torque because i am a stupid algebra two person designing a totaly new drive system and i want to have the math to show it is better. I do have help on doing them though.
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Last edited by Argoth : 16-10-2003 at 22:10.
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Unread 16-10-2003, 23:45
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There are several white papers available on this site that offer useful tools and tutorials regarding drivetrain design. Browse through all of the different categories to see what's of use to you.

Torque is equal to force x distance.
Friction is equal to the coefficient of friction (mu, a unitless experimental value) x the normal force.
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Unread 16-10-2003, 23:48
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Torque = Force * distance of lever arm from the point of force to the axis of rotation

Friction = Coefficient of friction (represented by the greek letter mu) * normal force

Depending on whether the object is moving or stationary determines the coefficient you use...Static coefficient for stationary objects, kinetic for moving objects.
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Unread 17-10-2003, 22:40
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Quote:
Originally posted by Jim McGeehin
Torque = Force * distance of lever arm from the point of force to the axis of rotation
To be a little bit more specific - Torque is a cross product. So, it is the distance from the axis of rotation to a point perpedicular to the force vector. Sorry to complicate things, but it can be very important in many applications.

Raul
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Unread 17-10-2003, 23:24
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I thank ya'll for the help with the physics equations my sponsor ( a physics teach) rattled them off at me and it kinda went over my head.
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Unread 23-10-2003, 20:58
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Quote:
Originally posted by Argoth
I thank ya'll for the help with the physics equations my sponsor ( a physics teach) rattled them off at me and it kinda went over my head.
So ask again, and write it down :-)
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Unread 25-10-2003, 17:18
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Quote:
the distance from the axis of rotation to a point perpedicular to the force vector.
I'm confused

points can be perpendicular?
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Unread 25-10-2003, 17:37
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Quote:
Originally posted by michael_obrien
I'm confused

points can be perpendicular?
If one were to draw a line from the axis of rotation to the point the force is acting upon, that line would be perpendicular to the component of the force vector exerting the torque.
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Unread 25-10-2003, 19:06
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Sometimes an example can be worth a thousand words (especially in physics).

Consider a rectangular body (represented by periods), that is acted on by a force F, and free to rotate about the point O.
Code:
......---> F
.    .
.    .
.    .
O.....
There are two ways to go about computing torque (which lead to the same thing). Torque = Force * moment arm. So to form the "moment arm", construct a "line of force" (a line paralell to the force vector), and drop a perpindicular line down to the point of rotation. This "perpindicular" is the moment arm, labeled 'm' below. The magnitude of the torque is therefore this value m multiplied by the magnitude of the force (torque = Fm). Note that this is a scalar equation.

Code:
  ---------> F
  |    .
m |    .
  |    .
  O.....
Alternatively, you could construct a vector whose initial point corresponds to O, the point of rotation, and whose final point corresponds to the point of application of the force F. You would then take the cross product of the vector F and the "OF" vector. Note that this is a vector equation.
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Unread 07-11-2003, 11:58
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Fricitonal Force Equations

Frictional force=mu* weight.

This works between surfaces, although beware of which mu value you have. Mu (Kinetic) is the frictional coefficient during motion, and Mu (Static) is for beginning motion.
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Unread 07-11-2003, 12:50
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Re: Fricitonal Force Equations

Quote:
Originally posted by Zil709
Frictional force=mu* weight.
*bzzzzz* wrong.

Frictional Force is mu * Normal force

The normal force is the force of the surface reacting against the robot, on a level surface this is equivalent to the object weight, but on a ramp or incline, this normal force is different. (The weight is split into some component forces).

This difference is an IMPORTANT distinction to make.


For more information contact your friendly neighborhood Physics Teacher/Professor/TA or pretty much any engineers you might know (although, they might have problems actually explaining it to you ).

John
Clarkson University PH131 Teaching Assistant
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Last edited by JVN : 07-11-2003 at 13:46.
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Unread 07-11-2003, 13:00
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