|
|
|
 "I got flour all over my Chromebook!" - frcguy [more] |
 |
|
|||||||
|
||||||||
|
|
Thread Tools | Rate Thread | Display Modes |
|
|
|
| "I got flour all over my Chromebook!" - frcguy [more] |
|
|
|||||||
|
||||||||
|
|
Thread Tools | Rate Thread | Display Modes |
|
#5
18-02-2002, 07:37
|
|||||
|
|||||
|
If you assume that the CG is in the center of the box, and that the box is at rest, wheel A will support more of the weight. You can do a quick free-body diagram to proove it to yourself. (See attached)
Notice that the forces balance, which is probably what your friends were thinking. But when you include the torques in the equation, the ground has to push on wheel a more than wheel b to keep the box from tipping. |
| Thread Tools | |
| Display Modes | Rate This Thread |
|
|
Similar Threads
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| weight distribution? | chrisw | Technical Discussion | 3 | 11-01-2003 13:25 |
| Weight Distribution Mechanism in Tread System? | Kai Zhao | Technical Discussion | 8 | 20-08-2002 16:38 |
| Lots of Wheels and F = u x N | archiver | 2001 | 17 | 23-06-2002 23:37 |
| Chief Delphi Site Question | Mike Bonham | General Forum | 1 | 16-02-2002 22:18 |
| Rookie Programmer has question about the default code | DanL | Programming | 3 | 26-01-2002 19:59 |
Threaded Mode