Maximum Score

[kevin.li.rit]

Knocking only one ball will trigger the release I assume?

[Dan Richardson]

The answer to your question.. tho it might not be possible is the highest score is 660pts

w/ 2 multipliers all balls and 2 bots hanging

technically tho.. w/ the 2 opponent bots hanging they can get 100 pts

however as we all know getting this many points would be useless except in finals

[KenWittlief]

Thulium - you forgot the 6 'starting balls' behind the wall on each end of the field - see drawings in section 4.1

Coffeism: I include 2 release balls in the 140 points count

and double all the 'small balls' is 280 - small size, not small value.

top score possible using only whats on your side of the field = 380 points

making it to the elimination rounds: Priceless!

[kevin.li.rit]

My mistake.

[KenWittlief]

Originally Posted by Coffeeism

Knocking only one ball will trigger the release I assume?

yes, either one - but if your opponent puts a release ball back onto your tee, then all the balls on the field jump back up into the ball release bin

(not really :c)

[Joe Ross]

Originally Posted by Thulium

It seems as though most of you are missing something. You want to win to advance and the points you get are the losers. So you would need to figure not the max amount of points you can accumulate during a match, but the max amount of points you can get to beat your opponent by only 20 points assuming all balls are scored and multiplied and all robots are hanging.

This would work out as:
Your alliance - (19 x 5 + 20(bonus balls)) x 2(multiplier) + 2 hanging = 330 pts
Their alliance - (17 x 5 + 20(bonus balls)) x 2(multiplier) + 2 hanging = 310 pts
your max points = 310 pts and the win of course

I get a different result, taking into account that there are the HP balls that you didn't account for and there and 3 multiplier balls:

Your alliance - (13 * 5 + 20(bonus balls)) * 4(multiplier) + 2 hanging = 440
Their alliance - (29 * 5 + 20(bonus balls)) * 2(multiplier) + 2 hanging = 430
your max points = 430 pts and the win of course

[piotrm]

I'm not sure if there is a maximum number of penalties or not, but would it not be possible for a team to continously goaltend and give the opposing team 10 or 20 points? Then do it again with the same ball ?

This would mean there is no maximum score (or minimum score). But I think first might DQ for too many penalties.

[kevin.li.rit]

Originally Posted by piotrm

I'm not sure if there is a maximum number of penalties or not, but would it not be possible for a team to continously goaltend and give the opposing team 10 or 20 points? Then do it again with the same ball ?

This would mean there is no maximum score (or minimum score). But I think first might DQ for too many penalties.

I think they would DQ, which is why I think that no team will build a robot that can goal tend, they'll either be useless or be disqualified when they try to goal tend.

[tkwetzel]

I have seen many inaccurate scores posted here. First of all, you need to assume a few things:
1) There are no goaltending penalties
2) There are no de-scoring penalties

If you did not assume those two things, your score could keep escalating until you ran out of time. However, assuming those two circumstances, you can score 380 while having your opponent score 375. If anyone would like this written out, let me know and I will show you how this is done.

[KenWittlief]

4.4.3 <G20>.. if a robot goaltends or descores any small ball, the referee will throw a green penalty flag and the opponents final score will be increased by twice the value of that small ball.

so if you block a 5 point shot, or knock a 5 point ball out of your opponents goal, they will get 10 points added after the match is over, for each offense.

I consider having your opponets score raised to be a penalty (for your team) you lost 10 or 20 points relative to their score.

[WakeZero]

Originally Posted by Joe Ross

I get a different result, taking into account that there are the HP balls that you didn't account for and there and 3 multiplier balls:

Your alliance - (13 * 5 + 20(bonus balls)) * 4(multiplier) + 2 hanging = 440
Their alliance - (29 * 5 + 20(bonus balls)) * 2(multiplier) + 2 hanging = 430
your max points = 430 pts and the win of course

I am getting this (I assume you can not get a 4x multiplier):

Winner: [(25 * 5) + (2 * 10)] * 2 + (2 * 50) = 390
Loser: [(23 * 5) + (2 * 10)] * 2 + (2 * 50) = 370

Remember, there are 6 HP balls on EACH side. Also, keep in mind that this score may not PHYSICALLY be possible if all of those balls don't fit into one goal

[tkwetzel]

"I am getting this (I assume you can not get a 4x multiplier):

Winner: [(25 * 5) + (2 * 10)] * 2 + (2 * 50) = 390
Loser: [(23 * 5) + (2 * 10)] * 2 + (2 * 50) = 370"

That is not correct. You could only have 24 5 point balls, making your score 380. Your opponent would have 24 small balls, however, you would have to put one of them in an uncapped goal. This would give that team 375 points. Because of the numbers of balls that can fit in a goal, I would put all 4 of the 10 points balls in the opponents capped goal, because 25 will not fit in the goal and still allow a cap to be placed on it. Moving the other 2 10 point balls to the opponents goal, would allow you to remove 4 of their 5 point balls to be placed in one of your two goals which would both be capped. And for people asking, you are not allowed to have more than a 2X multiplyer.

[KenWittlief]

what are you talking about?! you can get all 52 small balls on the field into ONE stationary goal

IF you (ummmmmm) adjust them before you throw them

but you will need one STRONG human player to make the necessary adjustments :^)

[tkwetzel]

Adjustments to those balls would most likely be considered destruction of the field. So you would still have a limit on the number on which will go into the goals.

[WakeZero]

Originally Posted by tkwetzel

"I am getting this (I assume you can not get a 4x multiplier):

Winner: [(25 * 5) + (2 * 10)] * 2 + (2 * 50) = 390
Loser: [(23 * 5) + (2 * 10)] * 2 + (2 * 50) = 370"

That is not correct. You could only have 24 5 point balls, making your score 380. Your opponent would have 24 small balls, however, you would have to put one of them in an uncapped goal. This would give that team 375 points. Because of the numbers of balls that can fit in a goal, I would put all 4 of the 10 points balls in the opponents capped goal, because 25 will not fit in the goal and still allow a cap to be placed on it. Moving the other 2 10 point balls to the opponents goal, would allow you to remove 4 of their 5 point balls to be placed in one of your two goals which would both be capped. And for people asking, you are not allowed to have more than a 2X multiplyer.

You are correct, by 5 points. The uncapped ball is a good idea