Using the extern keyword.

[rbayer]

Originally Posted by SeanCassidy

Hmm, when the variable is changed in user_routines.c, do you have to extern it back in u_r_f.c? Like so:

/*user_routines_fast.c*/
int foo = 263;
extern user_routines_function();    /*Is this extern needed?*/
extern foo = foo - 1;               /*Do we need the extern now,
                                     *because it was modified in u_r.c?*/

/*user_routines.c*/
user_routines_function()
{
  extern foo = foo + 3;
}

extern should never be used inside an expression like that. It is only used in declarations made at the file-scope level. Thus, you just do stuff like this:

/*user_routines_fast.c*/
int foo;

void myfunc(){
foo=foo+1;
}

/*user_routines.c*/
extern int foo;

void myfunc2(){
foo=foo+3;
}


They keyword extern is NEVER needed with function prototypes, as they are extern implicitly.

-Rob