Digital In Question

[Rickertsen2]

I'm assuming the rotary switch you are usign has a single common, and then a bunch of other pins. Pick a groung any ground on the RC and tie each of the other pins to a sig pin. Internaly, all of the gnd pins are connected to each other inside the RC.

[jacob_dilles]

Originally Posted by Rickertsen2

Internaly, all of the gnd pins are connected to each other inside the RC.

yep, all the grounds are solderd together inside the box. TECHNICLY you should run a ground wire from each that u use so that your not sinking more curent thurgh the ground then your drawing thrugh the postitives

lol BUT yes one wire will work fine and i doubt its even in the rules... becasue it doesnt realy matter

[Tom Bottiglieri]

ok i was just trying to figure out which pin the RC looks at when trying to see highs and lows.

[jacob_dilles]

when you set a pin to be an "input" in the initilzation code, it automaticly sets an internal pull up resistor. when the switch/rotor/encoder/aliean space ship is "off" as in OPEN the I/O reads a "1" on say "rc_dig_io01" or whatever the variable is. you then proceed to wire the switch to the pin and to ground. that way, when it is in the "on" i.e. "CLOSED" postion, the circut is shorted thrugh ground ( but its thrugh a 100 million billion ohm resistor so its not a problem ) and when you read it it calls it a "0"

so when your rotory switch, pic a ground pin, and solder that to the common. then for each "leg", solder it to inputs 1, 2, 3 etc ( actualy, id start at 7 if you dont have any, its an inturpt thing for future expandibity) so 7, 8, 9 etc. then to code it, you can either have a million

if a=0 and b=1 and c=1 and d=1 {do this}
if a=1 and b=0 and c=0 and d=1 {do this}
if a=0 and b=1 and c=0 and d=1 {do this}
if a=1 and b=0 and c=0 and d=1 {do this}

or you can have a switch statement. or NESTED switch statements.

or even better, you could have a lookup table! lol have fun with the code tho...