not robotics, but help would be appreciated

[impulse3D]

Originally Posted by LauraN

*drags out physics*

... power=I²R. So the amount of power you'd be drawing would decrease because you've decreased the resitance, but then increase proportionally the the square of the corresponding increase in current... I think I've totally confused myself...

Actually, all the stuff about increasing yet decreasing could be explained a lot clearer and in an easy-to-understand way.

Given V=IR and P=I²R; we know that IR is always constant because your voltage will remain constant, so IR can equal K. Essentially P=I(IR) [I just rearranged the variables under the commutative property], so P=KI. This shows that you need not worry about decreasing resistance, compensating in amperage, and increasing due to squaring; rather, there's just a simple linear relationship.

You could even graph it if you wanted to, whereas P=y, K=m, and I=x under the function y=mx+b! (b=0, obviously, because when your voltage is zero your IR HAS to be zero as well)