Tetra Math

[Dillon Compton]

Originally Posted by n0cturnalxb

Considering the goals (aside from the center one) are about 5'3" = 63"(.. that's almost as tall as I am! .. ugh, I feel short now) and each tetra is 2'4" = 28" ...

Let's say each tetra raises the stack about 3"?

And you need about 28" clearance left to fit the last tetra in ...

4? That doesn't sound right. 7ish-9ish?

I think I just fried my sleep-deprived brain.


(edit) Err, cross that out .. I mean around 4-6 maybe per stack.. maybe.. assuming each tetra raises each stack 3". I think. Someone check my math or logic or something, brain's not working well right now..

Assuming you can fit 4 perfect stacks of 4 inside the goal, that's 16.

I'd say go with stacking on top of the goal.. go for containing if you're having a lot of problems with designing the arm, but stacking will give you three times the amount of points you can get by containing .. and the possibility of making a row.

According to the kickoff, each tetra raises the stack approx. six inches.